# [Remove Duplicates from Sorted List][title]

## Description

Given a sorted linked list, delete all duplicates such that each element appear only *once*.

**Example 1:**

```
Input: 1->1->2
Output: 1->2
```

**Example 2:**

```
Input: 1->1->2->3->3
Output: 1->2->3
```

**Tags:** Linked List


## 思路

题意是删除链表中重复的元素，很简单，我们只需要遍历一遍链表，遇到链表中相邻元素相同时，把当前指针指向下下个元素即可。

```java
/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) { val = x; }
 * }
 */
class Solution {
    public ListNode deleteDuplicates(ListNode head) {
        if (head == null || head.next == null) return head;
        ListNode curr = head;
        while (curr.next != null) {
            if (curr.next.val == curr.val) {
                curr.next = curr.next.next;
            } else {
                curr = curr.next;
            }
        }
        return head;
    }
}
```


## 结语

如果你同我一样热爱数据结构、算法、LeetCode，可以关注我 GitHub 上的 LeetCode 题解：[awesome-java-leetcode][ajl]



[title]: https://leetcode.com/problems/remove-duplicates-from-sorted-list
[ajl]: https://github.com/Blankj/awesome-java-leetcode