{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# A. Нечетные буквы"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Вариант 1."
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"name = input()\n",
"new_name = ''\n",
"\n",
"\n",
"for i,char in enumerate(name):\n",
" if i % 2 != 0:\n",
" new_name += '?'\n",
" else:\n",
" new_name += char\n",
"print(new_name)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Вариант 2."
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"name = input()\n",
"new_name = ''\n",
"\n",
"\n",
"for i in range(len(name)):\n",
" if i % 2 != 0:\n",
" new_name += '?'\n",
" else:\n",
" new_name += name[i]\n",
"print(new_name)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# B. 100 раз подряд в квадрате"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"n = input()\n",
"print(int(100*n)**2)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# C. Дубли"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Вариант 1."
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"n = int(input())\n",
"a = [int(x) for x in input().split()]\n",
"\n",
"\n",
"b = []\n",
"b_set = set()\n",
"\n",
"\n",
"for item in a:\n",
" if item in b_set:\n",
" continue \n",
" else:\n",
" b.append(str(item))\n",
" b_set.add(item)\n",
"print(' '.join(b))"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Вариант 2."
]
},
{
"cell_type": "code",
"execution_count": 6,
"metadata": {},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"1 2 3 3 3 1 2 1 4 1 1 1\n",
"1 2 3 4\n"
]
}
],
"source": [
"nums = input()\n",
"nums_sep = nums.split()\n",
"new_nums = []\n",
"for num in nums_sep:\n",
" if num not in new_nums:\n",
" new_nums.append(num)\n",
"print(' '.join(new_nums))"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# D. Дубли-2"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"phrase = input()\n",
"new_phrase = phrase[0]\n",
"\n",
"\n",
"for char in phrase[1:]:\n",
" if new_phrase[-1] == char:\n",
" continue \n",
" else:\n",
" new_phrase += char\n",
" \n",
"print(new_phrase)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# E. Магический амулет"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"from math import pi \n",
"\n",
"\n",
"def get_sq(r):\n",
" return pi * r ** 2\n",
"\n",
"\n",
"r = float(input())\n",
"print(get_sq(r))"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# F. Числа Фибоначчи"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Вариант 1."
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"n = int(input())\n",
"def app_fib(n):\n",
" '''\n",
" approximate fibonacci function\n",
" two roots z^2 - z - 1 = 0\n",
" |z_1| > 1, |z_2| < 1\n",
" '''\n",
" q5 = 5 ** 0.5\n",
" return ((1 + q5) / 2) ** n / q5\n",
"\n",
"# fast fibonacci function\n",
"def fast_fib(n):\n",
" '''\n",
" fast fibonacci function\n",
" '''\n",
" return round(app_fib(n))\n",
"\n",
"print(fast_fib(n))"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Вариант 2"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"n = int(input())\n",
"fib = []\n",
"if n == 1 or n == 2:\n",
" print(1)\n",
"else:\n",
" fib = [1, 1]\n",
" for i in range(2, n):\n",
" fib.append(fib[i - 1] + fib[i - 2])\n",
" print(fib[n - 1])"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# G. Я есть Грут. "
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Вариант 1."
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"phrases = input()\n",
"print(phrases)\n",
"# выкидываем пробелы после предложения (чтобы не обрабатывать кучу случаев) и сплитим по точке\n",
"phrases = phrases.replace('. ', '.').split('.')\n",
"# если в конце предложения была точка, сплит запишет отдельным элементом пустой символ. \n",
"# дропаем его\n",
"if phrases[-1] == '':\n",
" phrases.pop()\n",
"# делаем лист для записи развернутых предложений\n",
"new_separated_phrases = []\n",
"\n",
"for phrase in phrases:\n",
" # сплит слов по пробелу\n",
" separated_phrase = phrase.split(' ')\n",
" # разворот\n",
" separated_phrase.reverse()\n",
" # сборка строки и запись с заглвной буквы\n",
" new_phrase = ' '.join(separated_phrase).lower().capitalize()\n",
" # добавление в лист развернутых предложений\n",
" new_separated_phrases.append(new_phrase)\n",
"# сборка отдельных предложений в единый текст\n",
"new_phrase = '. '.join(new_separated_phrases) + '.'\n",
"print(new_phrase)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Вариант 2."
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"phrases = input()\n",
"phrases = phrases.replace('. ', '.').lower().split('.')\n",
"reversed_phrases = [phrase.split(' ')[::-1] for phrase in phrases if len(phrase) > 0]\n",
"reverse_phrase_all = [' '.join(phrase).capitalize() for phrase in reversed_phrases]\n",
"print('. '.join(reverse_phrase_all) + '.')"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"Напишите \"функцию голосования\", def Election(x, y, z), возвращающую то значение (True или False), которое среди значений ее аргументов x, y, z встречается чаще.\n"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# H. Голосование"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Вариант 1. "
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"input_str = input()\n",
"x, y, z = map(int, input_str.split(' '))\n",
" \n",
"def Election(x, y, z):\n",
" if x + y + z < 2:\n",
" return 0\n",
" else:\n",
" return 1\n",
" \n",
"print(Election(x, y, z))"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Вариант 2. "
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"def Election(x,y,z):\n",
" if x < 1 and y < 1 or x < 1 and z < 1 or z < 1 and y < 1:\n",
" return 0\n",
" else:\n",
" return 1\n",
" \n",
"d = input().split()\n",
"d = list(d)\n",
"x = int(d[0])\n",
"y = int(d[1])\n",
"z = int(d[2])\n",
"print(Election(x, y, z))"
]
}
],
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"language": "python",
"name": "python3"
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"file_extension": ".py",
"mimetype": "text/x-python",
"name": "python",
"nbconvert_exporter": "python",
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