******* Cycles ******* Thermal machines cycles and efficiency (def) ============================================ We consider in this section thermal machines working between two thermal reservoirs. In these machines, the *working fluid* is the thermodynamic system that exchange thermal energies between a hot reservoir (at temperature :math:`T_H`) and a cold one (at temperature :math:`T_C`). Following results of :numref:`Sec:chap2:EnergyConversion`, it can supply mechanical energy (it is thus a *heat engine*) or absorb mechanical energy (it can be a *heat pump* or *refrigerator*). Evolutions during a cycle ------------------------- In a thermal machine, the *working fluid* is evolving on a thermodynamic cycle. Let us consider a transformation :math:`a` from a state 1 to a state 2 as represented on :numref:`Fig:chap2:cycle` .. _Fig:chap2:cycle: .. figure:: ./_static/fig/chap2/cycle.png :scale: 30% :align: center Entropic diagram representing thermal energy exchanged during a cycle. During reversible transformation from 1 to 2, the heat exchanged is positive and corresponds to the hatched area. During this transformation, the fluid is absorbing thermal energy :math:`Q_{1\rightarrow 2}>0`. For the return from state 2 to 1, the fluid will supply thermal energy :math:`Q_{2\rightarrow 1}<0`. Thus two possibilities occurs: * The fluid follows transformation :math:`m` (in blue): :math:`|Q_{2\rightarrow 1}|<|Q_{1\rightarrow 2}|` such that the thermal energy exchanged during cycle is *positive*. The application of first principle immplies that the mechanical work will be negative: this is a **heat engine**. * The fluid follows transformation :math:`h` (in red): :math:`|Q_{2\rightarrow 1}|>|Q_{1\rightarrow 2}|` such that the thermal energy exchanged during cycle is *negative*. The application of first principle immplies that the mechanical work will be positive: this can be a **heat pump** or a **refirgerators**. From this observation, one can observe several things: .. admonition:: Remarks * When a cycle is followed clockwise in the entropic diagram (T,S), the cycle is describing a *heat engine* * When a cycle is followed reversed clockwise in the entropic diagram (T,S), the cycle is describing a *heat pump* or a *refrigerator* * Any cycle can be used as a basis to develop a thermal machine. Energy conversion efficiency ---------------------------- The economice notion of efficiency is generally defined by the ratio bewteen the *usefull energy provided* by the machine and its *energy absorption*, or in other words the ratio between benefits of a thermodynamic system and costs: .. math:: \eta \equiv \frac{\text{benefits}}{\text{costs}} Heat engine and thermal efficiency ********************************** For a heat engine, a mechanical energy :math:`-W` is produced (benefit) from a thermal energy absorption from *hot source* :math:`Q_H` (cost). This defines the **thermal efficiency** of the *heat engine*: .. math:: \eta_{th} = \frac{-W}{Q_H} Thanks to the first principle, it can also be written as: .. math:: :label: thEfficiency \eta_{th} = \frac{Q_H + Q_C}{Q_H} = 1 + \frac{Q_C}{Q_H} = 1 - \frac{|Q_C|}{|Q_H|} .. admonition:: Remark * For internal combustion engines, the thermal efficiency is about 25% for gasoline engines and 40% for diesel engines. For gas turbine, the thermal efficiency can reach 60%. * A great part of chemical energy (from fuel combustion) is then dissipated in heat and released in environnement (to the *cold sink*). Heat generators and coefficient of performance (COP) **************************************************** For a *heat pump* or *refrigerators*, a mechanical energy :math:`W` is consumed (cost) and the benefits depend on the usefull thermal energy exchanged. Because these ratio are generally greater than 1, we talk about **coefficient of performance**: For a *heat pump* : .. math:: :label: COPhp COP_{HP} = \frac{-Q_H}{W} = \frac{Q_H}{Q_H+Q_C} = \frac{1}{1 + \frac{Q_C}{Q_H}} = \frac{1}{1 - \frac{|Q_C|}{|Q_H|}} For a *refrigerator* : .. math:: :label: COPr COP_{R} = \frac{Q_C}{W} = \frac{Q_C}{-Q_H-Q_C} = \frac{1}{-\frac{Q_H}{Q_C}-1} = \frac{1}{\frac{|Q_H|}{|Q_C|}-1} Carnot cycle ============ If a thermal machine is working between two TER in a reversible maneer, then it must exchange with both TER following isothermal transformation. These two isothermal transformation can thus be linked using: - 2 isentropes: this is the **Carnot cycle** - 2 isochores: this is the **Stirling cycle** - 2 isobares: this is the **Ericsson cycle** These three cycles are ideal cycles for a thermal machine working between two TER and serve as reference cycle providing the maximum thermal efficiencies/COP. .. _Sec:chap2:Carnot: Carnot heat engine ------------------ .. _Fig:chap2:CarnotCycle: .. figure:: ./_static/fig/chap2/CarnotCycle.png :scale: 30% :align: center Carnot cycle (for a heat engine). It is easy to remark that in the reversible isothermes, we have :math:`Q_C = T_C (S_1-S_2)` and :math:`Q_H = T_H (S_2-S_1)`, such that thanks to equation :eq:`thEfficiency`, it is easy to show that: .. math:: :label: CarnotThEff \eta_{th,C} = 1 - \frac{T_C}{T_H} As :math:`T_H>T_C`, the carnot thermal efficiency is always lower than 1. .. admonition:: Remark * The Carnot thermal efficiency gives the maximum efficiency that can be reached by a heat engine between two TER. * For example, the Carnot thermal efficiency of a thermal power plant beteen :math:`T_H = 1000 K` (combustion temperature) and :math:`T_C = 300 K` (ambiant) is about 70%. Real thermal efficiency of such power plant reaches 40% because of non reversibility. .. _Sec:chap2:CarnotHeatGen: Carnot heat pump/refrigerators ------------------------------ .. _Fig:chap2:CarnotCycleGen: .. figure:: ./_static/fig/chap2/CarnotCycleGen.png :scale: 30% :align: center Carnot cycle (for a heat generator: heat pump or refrigerator). This times, in the reversible isothermes, we have :math:`Q_C = T_C (S_2-S_1)` and :math:`Q_H = T_H (S_1-S_2)`. If this is a heat pump, the coefficient of performance :eq:`COPhp` becomes: .. math:: :label: CarnotCOPhp COP_{HP,C} = \frac{1}{1 - \frac{T_C}{T_H}} > 1 If this is a refrigerator, the coefficient of performance :eq:`COPr` becomes: .. math:: :label: CarnotCOPr COP_{R,C} = \frac{1}{\frac{T_H}{T_C}-1} If the :math:`COP_{HP,C}` of a heat pump is greater than 1, we cannot conclude for a refrigerator. Other cycles ============ It is shown that the thermal efficiency of a Carnot's cycle is the better thermal efficiency a heat engine can reach between two TER. It is let to the reader to apply the same reasonement to a heat pump or refrigerator. Heat engine Reversible cycles ----------------------------- If we consider any **reversible cycle**, there are two possibilities: 1. If the cycle is working between the two TER :math:`T_C` and :math:`T_H`, then it will have the same thermal efficiency as Carnot cycle. 2. Otherwise, it can be decomposed in an infinity of reversible cycles :math:`i` working between two TER whith temperatures :math:`T_{Ci} > T_C` and :math:`T_{Hi} < T_H` who have a thermal efficiency lower than Carnot efficiency between :math:`T_C` and :math:`T_H`. As a result, the global efficiency will be lower than Carnot's efficiency. Heat engine irreversible cycles ------------------------------- Thanks to second principle of thermodynamics, a *heat engine* that exchange between two TER during a cycle will guarantee that (equation :eq:`secondPpeCycle`): .. math:: \frac{Q_H}{T_H} + \frac{Q_C}{T_C} \le 0 \text{ (0 if reversible cycle)} That can be rewritten as: .. math:: \frac{|Q_H|}{T_H} - \frac{|Q_C|}{T_C} \le 0 Or: .. math:: -\frac{T_C}{T_H} \ge -\frac{|Q_C|}{|Q_H|} And finally, thanks to relation :eq:`thEfficiency`, the thermal efficiency of a heat pump reads: .. math:: \eta_{th} = 1 - \frac{|Q_C|}{|Q_H|} \le 1 - \frac{T_C}{T_H} In other words, the thermal efficiency of any irreversible cycle between two TER will be lower than the Carnot's thermal efficiency. Importance of Carnot cycle ========================== .. caution:: **Carnot cycle**, as any reversible cycle working between two TER (Ericsson, Stirling, etc.) may serve as reference for real cycles describing thermal machines : * In a *heat engine*, thermal exchanged cannot be represented by isothermal transformations. It is more often isobaric/isochore transformations (or a combination of both). * In a *heat pump* (or *refrigerator*), it is possible to be close to isothermal transformations during heat exchanges using phase change properties of a liquid-vapor couple (:math:`p^{sat}(T)`). * Whatever the system is, transformations will be non reversibles.