# 第五章 《循环和关系表达式》 编程练习题之我解 ## 5.1 **题:** 编写一个要求用户输入两个整数的程序。该程序将计算并输出这两个整数之间(包括这两个整数)所有整数的和。这里假设先输入较小的整数。例如,用户输入的是2和9,则程序将指出2~9之间所有整数的和为44。 **解:** ```Cpp #include int main() { using namespace std; int number1, number2; cout << "Enter the first number: "; cin >> number1; cout << "Enter the second number: "; cin >> number2; if (number1 > number2) { int tmp; tmp = number1; number1 = number2; number2 = tmp; } int s = 0; for (int num=number1; num < number2+1; ++num) { s += num; } cout << "Sum the number from " << number1 << " to " << number2 << ", sum = " << s << endl; return 0; } ``` ## 5.2 **题:** 使用 `array` 对象(而不是数组)和 `long double`(而不是 `long long`)重新编写程序清单5.4,并计算 100! 的值。 **解:** ```Cpp #include #include const int ar_size = 100; int main() { using namespace std; array factorials; factorials[0] = factorials[1] = 1; for (int i = 2; i < ar_size+1; ++i) { factorials[i] = i * factorials[i-1]; } for (int i = 0; i < ar_size + 1; ++i) { cout << i << "! = " << factorials[i] << "\n"; } cout << endl; return 0; } ``` ## 5.3 **题:** 编写一个要求用户输入数字的程序。每次输入后,程序都将报告到目前为止,所有输入的累计和。当用户输入 0 时,程序结束。 **解:** ```Cpp #include int main() { using namespace std; double s = 0; double ch; while (1) { cout << "Enter a number (int/double) (0 to exit): "; cin >> ch; if (ch == 0) { break; } s += ch; cout << "Until now, the sum of the number you inputed is: " << s << endl; } return 0; } ``` ## 5.4 **题:** Daphne以10%的单利投资了100美元。也就是说,每一年的利润都是投资额的10%,即每年10美元。而Cleo以5%的复利投资了100美元。也就是说,利息是当前存款(包括获得的利息)的5%,Cleo在第一年投资100美元的盈利是5%—得到了105美元。下一年的盈利是105美元的5%—即5.25美元,依此类推。请编写一个程序,计算多少年后,Cleo的投资价值才能超过Daphne的投资价值,并显示此时两个人的投资价值。 **解:** ```Cpp #include int main() { using namespace std; double daphne_account = 100; double cleo_account = 100; int year = 0; while (cleo_account <= daphne_account) { ++year; daphne_account += 10; cleo_account += cleo_account * 0.05; } cout << "After " << year << " Years. " << "Cleo's account is " << cleo_account << " while more than the one of Daphne which is " << daphne_account << "." << endl; return 0; } ``` ## 5.5 **题:** 假设要销售《C++ For Fools》一书。请编写一个程序,输入全年中每个月的销售量(图书数量,而不是销售额)。程序通过循环,使用初始化为月份字符串的 `char *` 数组(或 `string` 对象数组)逐月进行提示,并将输入的数据储存在一个int数组中。然后,程序计算数组中各元素的总数,并报告这一年的销售情况。 **解:** ```Cpp #include #include int main() { using namespace std; string months[12] = {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}; int sell[12]; int total_sales = 0; cout << "Enter the sales of book <> each month." << endl; for (int i=0; i < 12; ++i) { cout << months[i] << ":"; cin >> sell[i]; total_sales += sell[i]; } cout << "\nThe total sales is " << total_sales << endl; for (int i=0; i < 12; ++i) { cout << months[i] << ": " << sell[i] << endl; } return 0; } ``` ## 5.6 **题:** 完成编程练习5,但这一次使用一个二维数组来存储输入——3年中每个月的销售量。程序将报告每年销售量以及三年的总销售量。 **解:** ```Cpp #include #include int main() { using namespace std; string months[12] = {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}; int sells[3][12]; int total_sales[3] = {0, 0, 0}; for (int i=0; i<3; ++i) { cout << "Enter " << i+1 << " year(s) sales of book <> each month." << endl; for (int j=0; j<12; ++j) { cout << months[j] << ": "; cin >> sells[i][j]; total_sales[i] += sells[i][j]; } } for (int i=0; i<3; ++i) { cout << i+1 << " year(s) total sales is " << total_sales[i] << endl; } cout << "There years total sales is " << total_sales[0] + total_sales[1] + total_sales[2] << endl; return 0; } ``` ## 5.7 **题:** 设计一个名为 `car` 的结构体,用它存储下述有关汽车的信息:生产商(存储在字符数组或 `string` 对象中的字符串)、生产年份(整数)。编写一个程序,向用户询问有多少辆汽车。随后,程序使用new来创建一个由相应数量的 `car` 结构体组成的动态数组。接下来,程序提示用户输入每辆车的生产商(可能由多个单词组成)和年份信息。请注意,这需要特别小心,因为它将交替读取数值和字符串(参见第4章)。最后,程序将显示每个结构的内容。该程序的运行情况如下: How many cars do you wish to catalog? 2 Car #1: Please enter the maker: Hudson Hornet Please enter the year made: 1952 Car #2: Please enter the maker: Kaiser Please enter the year made: 1951 Here is your collection: 1952 Hudson Hornet 1951 Kaiser **解:** ```Cpp #include #include int main() { using namespace std; struct Car { string company; int year; }; int car_num = 0; cout << "How many cars do you wish to catalog? "; cin >> car_num; cin.get() // 读取输入流末尾的回车 Car *cars = new Car[car_num]; for (int i=0; i < car_num; ++i) { cout << "Please enter the maker: "; cin >> (cars+i)->company; cout << "Please enter the year made: "; cin >> (cars+i)->year; } cout << "\nHere is your collection: \n"; for (int i=0; i < car_num; ++i) { cout << cars[i].year << " " << cars[i].company << endl; } delete [] cars; return 0; } ``` ## 5.8 **题:** 编写一个程序,它使用一个 `char`数组和循环,每次读取一个单词,直到用户输入 `done` 为止。随后,该程序指出用户输入了多少个单词(不包括done在内)。下面是该程序的运行情况: Enter words (type 'done' to stop): anteater birthday category dumpster envy finagle genometry done for sure You entered a total of 7 words. > 您应在程序中包含头文件 `cstring`,并使用函数 `strcmp()` 来进行比较测试。 **解:** ```Cpp #include #include int main() { using namespace std; int word_count = 0; char ch[80]; cout << "Enter a word (type 'done' to stop the program.): \n"; do { cin >> ch; if (strcmp(ch, "done") != 0) { word_count++; } } while (strcmp(ch, "done") != 0); cout << "\nYou entered a total of " << word_count << " words." << endl; return 0; } ``` ## 5.9 **题:** 编写一个满足前一个练习中描述的程序,但使用 `string` 对象而不是字符数组。请在程序中包含头文件 `string`,并使用关系运算符来进行 比较测试。 **解:** ```Cpp #include #include int main() { using namespace std; int word_count = 0; string ch; cout << "Enter a word (type 'done' to stop the program.): \n"; do { cin >> ch; if (ch != "done") { word_count++; } } while (ch != "done"); cout << "\nYou entered a total of " << word_count << " words." << endl; return 0; } ``` ## 5.10 **题:** 编写一个使用嵌套循环的程序,要求用户输入一个值,指出要显示多少行。然后,程序将显示相应行数的星号,其中第一行包括一个星号,第二行包括两个星号,依此类推。每一行包含的字符数等于用户指定的行数,在星号不够的情况下,在星号前面加上句点。该程序的运 行情况如下: Enter number of rows: 5 Output: ....* ...** ..*** .**** ***** **解:** ```Cpp #include int main() { using namespace std; int line_num = 0; cout << "Enter the number of rows: "; cin >> line_num; cout << "Output:" << endl; for (int i = line_num; i > 0; --i) { for (int j = i-1; j > 0; --j) { cout << "."; } for (int j = line_num - (i-1); j > 0; --j) { cout << "*"; } cout << "\n"; } return 0; } ```