{
 "cells": [
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Popcorn Hack 1"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 27,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[5, 8, 11, 14, 17]\n"
     ]
    }
   ],
   "source": [
    "x = [1,2,3,4,5]\n",
    "y = []\n",
    "def f(x):\n",
    "    for i in x:\n",
    "        y.append(3*(i+2)-4)\n",
    "    return y\n",
    "print(f(x))"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Popcorn Hack 2"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 7,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "103.0\n"
     ]
    }
   ],
   "source": [
    "num1 = 20 ## num1 is 20\n",
    "num2 = num1 /2 ## num2 is num1 divided by 2\n",
    "## Num2 is 10\n",
    "num3 = num2 * 10 + 3 ## num3 is num2 times 10 plus 3\n",
    "## num3 will be 100 + 3\n",
    "print(num3) ## prints num3\n",
    "\n",
    "## code will print 103"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Popcorn Hack 3"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 9,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "35\n",
      "5\n",
      "300\n",
      "1.3333333333333333\n",
      "5\n"
     ]
    }
   ],
   "source": [
    "num1 = 20\n",
    "num2 = 15\n",
    "\n",
    "print(num1 + num2)\n",
    "## Prints Addition\n",
    "\n",
    "print(num1 - num2)\n",
    "## Prints Subtraction\n",
    "\n",
    "print(num1 * num2)\n",
    "## Prints Multiplication\n",
    "\n",
    "print(num1 / num2)\n",
    "## Prints Division\n",
    "\n",
    "print(num1 % num2)\n",
    "## Prints MOD\n"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Popcorn Hack 4"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 20,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Torin Wolff\n",
      "5\n",
      "ri\n"
     ]
    }
   ],
   "source": [
    "lastname = \"Wolff\"\n",
    "firstname = \"Torin\"\n",
    "print(firstname + \" \" + lastname)\n",
    "lenthlast=len(lastname)\n",
    "print (lenthlast)\n",
    "substringfirstname=firstname[2:4]\n",
    "print(substringfirstname)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Homework Hacks\n",
    "\n",
    "Using the three commands MOVE_FORWARD(), ROTATE_RIGHT(), ROTATE_LEFT(), and CAN_MOVE(). solving the problem. Command Sequence:CAN_MOVE(true), MOVE_FORWARD(), MOVE_FORWARD, MOVE_FORWARD(). ROTATE_LEFT(), MOVE_FORWARD(), MOVE_FORWARD(),  ROTATE_RIGHT(), MOVE_FORWARD(), MOVE_FORWARD(), MOVE_FORWARD(). End of path."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 26,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "55\n"
     ]
    }
   ],
   "source": [
    "def fibonacci(number):\n",
    "    if number == 0:\n",
    "        return 0 ## if n is 0, return 0\n",
    "    elif number == 1:\n",
    "        return 1 ## if n is 1, return 1\n",
    "    else:\n",
    "        return fibonacci(number - 1) + fibonacci(number - 2) ## if n is not 0 or 1, return the sum of the previous two numbers\n",
    "    \n",
    "print(fibonacci(10)) ## prints the 10th number in the fibonacci sequence. Can change to any number but 10 is a high number."
   ]
  }
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