# The precise statement being claimed This file pins exactly what the entry asserts, so a reviewer can check the formal claim against the informal question before checking any arithmetic. It is the analogue of the Lean statement anchor used in earlier submissions: no proof, just the statement, stated once and unambiguously. ## The question, as posed Lorist and Schwenninger, "A solution to Crouzeix's conjecture", arXiv:2608.03841v1 (4 August 2026), prove their Lemma 1 — a perturbation result for 2-dilations — and then remark: > **Remark 2.** Inequality (5) alone implies that kappa <= 1 + sqrt(1 - Re). > Thus, if it were known that Re >= 0, the assertion of Lemma 1 would > already follow. However, it is unclear whether Re >= 0 in general and > the lower bound in (4) already suffices in our proof. The objects are those of Lemma 1 and its proof: - H a finite-dimensional complex Hilbert space, T in L(H), kappa := ||T||; - K a Hilbert space, Q in L(K) a contraction, V in L(H,K) an isometry; - E_n := 2 V* Q*^n V - T*^n, assumed uniformly bounded and to commute with T; - x in H with ||x|| = 1 and T*T x = kappa^2 x, chosen in the branch kappa > 1 (the proof opens "If kappa <= 1, there is nothing to prove, so suppose kappa > 1"). Inner products are linear in the first variable (their Section 1). The quantity Re is invariant under that choice: swapping to the second variable replaces the inner product by its complex conjugate, and only its real part is used. ## The claim **The answer is no.** There is a configuration satisfying every hypothesis of Lemma 1, with kappa > 1, and Re < 0. Concretely, taking Omega to be the open unit disk and building V, Q and E_1 exactly as the proof of their Theorem 3 builds them — K = L^2(dOmega, |dsigma|; H), (Vx)(sigma) = 2^{-1/2} P_Omega(sigma)^{1/2} x, Q = multiplication by f, T = f(A) — with A = [[1/2, 9/10], [0, 1/2]], f(z) = (8 - 19 z)/(19 - 8 z), we have kappa = sqrt(594 sqrt(90709) + 178918)/500 = 1.196358697123234... > 1, Re = -4/95 - 1188 sqrt(90709)/8617355 = -0.083626247971819... < 0. Both are algebraic numbers; the second has minimal polynomial 163729745 X^2 + 13787768 X + 8000. The largest singular value of T is simple, so x is determined up to a phase and no choice is being made. **Minimality.** No 1x1 configuration can be a counterexample: there T = f(a) is a scalar with a in Omega, so kappa = |f(a)|/||f||_inf <= 1 by the maximum principle and the branch kappa > 1 is never entered. So 2x2 is the smallest possible, and it is attained. ## What is NOT claimed - Nothing about the correctness of the paper. Inequalities (4) and (5) both hold at this witness, and so does the theorem (kappa <= 2). Only the shortcut proposed in Remark 2 fails. - No claim about non-disk domains Omega. Every configuration here uses a disk. - No claim of priority over the Crouzeix conjecture itself, which is settled by two independent 2026 proofs (Jin; Lorist-Schwenninger) and is not at issue.