{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "## Mathematics in MarkDown " ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "#### Inline Equation : \n", "\n", "Pythogorous Theorem : \\$ x^2 + y^2 = 1 \\$ \n", "\n", "Pythogorous Theorem : $ x^2 + y^2 = 1 $ \n", "\n", "#### Simple display of Equation : \n", "\n", "Pythogorous Theorem : \\$\\$ x^2 + y^2 = 1 \\$\\$ \n", "\n", "Pythogorous Theorem : $$ x^2 + y^2 = 1 $$ " ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Breckets" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "Markdown|Letter\n", "--|--\n", "( \\big( | $ ( \\big( $\n", "\\Big( \\bigg( \\Bigg( | $ \\Big( \\bigg( \\Bigg( $ \n", "\\big] \\Big] \\bigg] \\Bigg] | $ \\big] \\Big] \\bigg] \\Bigg] $\n", "\\big\\{ \\Big\\{ \\bigg\\{ \\Bigg\\{ | $ \\big\\{ \\Big\\{ \\bigg\\{ \\Bigg\\{ $\n", "\\big \\langle \\Big \\langle \\bigg \\langle \\Bigg \\langle | $ \\big \\langle \\Big \\langle \\bigg \\langle \\Bigg \\langle $\n", "\\big \\rangle \\Big \\rangle \\bigg \\rangle \\Bigg \\rangle | $ \\big \\rangle \\Big \\rangle \\bigg \\rangle \\Bigg \\rangle $" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Integrals\n", "\n", " MarkDown |       Symbol                 |\n", "--------------------------------- |-------------------------------\n", " \\int_{lower}^{upper} | $ \\int_{lower}^{upper} $ \n", " \\iint_{lower}^{upper} | $ \\iint_{lower}^{upper} $ \n", " \\iiint_{lower}^{upper} | $ \\iiint_{lower}^{upper} $ \n", " \n", " **\\int_{a}^{x} x^2 dx** $$ \\int_{a}^{x} x^2 dx $$ \n", " **\\iint_V \\mu(u,v) \\,du\\,dv** $$ \\iint_V \\mu(u,v) \\,du\\,dv $$ \n", " **\\iiint_V \\mu(u,v,w) \\,du\\,dv\\,dw** $$ \\iiint_V \\mu(u,v,w) \\,du\\,dv\\,dw $$\n", " " ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Sums and products \n", "Inline **\\sum_{n=1}^{\\infty} 2^{-n} = 1** $ \\quad\\quad\\sum_{n=1}^{\\infty} 2^{-n} = 1 $ \n", "\n", "** \\sum_{n=1}^{\\infty} 2^{-n} = 1 ** $$ \\sum_{n=1}^{\\infty} 2^{-n} = 1 $$ \n", "** \\prod_{i=a}^{b} f(i) ** $$ \\prod_{i=a}^{b} f(i) $$ \n" ] }, { "cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": [] }, { "cell_type": "markdown", "metadata": {}, "source": [ "Assume we have the next sets\n", "\n", "$$`\n", "S = \\{ z \\in \\mathbb{C}\\, |\\, |z| < 1 \\} \\quad \\textrm{and} \\quad S_2=\\partial{S}\n", "$$" ] }, { "cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": [] } ], "metadata": { "anaconda-cloud": {}, "kernelspec": { "display_name": "Python 3", "language": "python", "name": "python3" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 3 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython3", "version": "3.5.4" } }, "nbformat": 4, "nbformat_minor": 2 }