/* * Copyright (c) 2017 Kotlin Algorithm Club * * Permission is hereby granted, free of charge, to any person obtaining a copy * of this software and associated documentation files (the "Software"), to deal * in the Software without restriction, including without limitation the rights * to use, copy, modify, merge, publish, distribute, sublicense, and/or sell * copies of the Software, and to permit persons to whom the Software is * furnished to do so, subject to the following conditions: * * The above copyright notice and this permission notice shall be included in all * copies or substantial portions of the Software. * * THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR * IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY, * FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE * AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER * LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, * OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE * SOFTWARE. */ package io.uuddlrlrba.ktalgs.sorts /** * Invented in 1945 by John von Neumann, merge sort is an efficient algorithm using the divide and conquer approach * which is to divide a big problem into smaller problems and solve them. Conceptually, a merge sort works as follows: * 1) Divide the unsorted list into n sublists, each containing 1 element (a list of 1 element is considered sorted). * 2) Repeatedly merge sublists to produce new sorted sublists until there is only 1 sublist remaining. */ @ComparisonSort @StableSort class MergeSort: AbstractSortStrategy() { override fun > perform(arr: Array) { val aux = arr.clone() sort(arr, aux, 0, arr.size - 1) } private fun > sort(arr: Array, aux: Array, lo: Int, hi: Int) { if (hi <= lo) return val mid = (lo + hi) / 2 sort(arr, aux, lo, mid) sort(arr, aux, mid + 1, hi) merge(arr, aux, lo, mid, hi) } private fun > merge(arr: Array, aux: Array, lo: Int, mid: Int, hi: Int) { System.arraycopy(arr, lo, aux, lo, hi - lo + 1) var i = lo var j = mid + 1 for (k in lo..hi) { when { i > mid -> arr[k] = aux[j++] j > hi -> arr[k] = aux[i++] aux[j] < aux[i] -> arr[k] = aux[j++] else -> arr[k] = aux[i++] } } } }