<!doctype html> <html class="no-js" lang="en"> <head> <meta charset="utf-8" /> <meta name="viewport" content="width=device-width, initial-scale=1.0" /> <title> 解题 - 语时lab </title> <link href="atom.xml" rel="alternate" title="语时lab" type="application/atom+xml"> <link rel="stylesheet" href="asset/css/foundation.min.css" /> <link rel="stylesheet" href="asset/css/docs.css" /> <script src="asset/js/vendor/modernizr.js"></script> <script src="asset/js/vendor/jquery.js"></script> <script src="asset/highlightjs/highlight.pack.js"></script> <link href="asset/highlightjs/styles/github.css" media="screen, projection" rel="stylesheet" type="text/css"> <script>hljs.initHighlightingOnLoad();</script> <script type="text/javascript"> function before_search(){ var searchVal = 'site:cshishaliu.github.io ' + document.getElementById('search_input').value; document.getElementById('search_q').value = searchVal; return true; } </script> </head> <body class="antialiased hide-extras"> <div class="marketing off-canvas-wrap" data-offcanvas> <div class="inner-wrap"> <nav class="top-bar docs-bar hide-for-small" data-topbar> <section class="top-bar-section"> <div class="row"> <div style="position: relative;width:100%;"><div style="position: absolute; 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}); </script> <div class="row"> <div class="large-8 medium-8 columns"> <div class="markdown-body home-categories"> <div class="article"> <a class="clearlink" href="15863333927200.html"> <h1>数列不等式 `lhc@jinan|20200407`</h1> <div class="a-content"> <div class="a-content-text"> <p>已知数列 \(\{a_n\}\) 满足 \(a_1 = 1\), \(a_n a_{n+1} = n\), \(n = 1,2,3,\dots\). 求证: <br/> \[<br/> \frac1{a_1} + \frac1{a_2} + \frac1{a_3} + \dots + \frac1{a_n} \ge 2 \sqrt n - 1.<br/> \]</p> </div> </div> </a> <div class="read-more clearfix"> <div class="more-left left"> <a href="15863333927200.html">Read more</a> <span class="date">2020/04/08</span> <span>posted in </span> <span class="posted-in"><a href='problemsolving.html'>解题</a></span> </div> <div class="more-right right"> <span class="comments"> </span> </div> </div> </div><!-- article --> <div class="article"> <a class="clearlink" href="15840603466913.html"> <h1>二元有理函数最值</h1> <div class="a-content"> <div class="a-content-text"> <p>已知 \(x,y > 0\), 求 <br/> \[<br/> \frac{(2x+1) (y+1)}{2x^2 + 5y^2 + 7}<br/> \]<br/> 的最大值.</p> </div> </div> </a> <div class="read-more clearfix"> <div class="more-left left"> <a href="15840603466913.html">Read more</a> <span class="date">2020/03/13</span> <span>posted in </span> <span class="posted-in"><a href='problemsolving.html'>解题</a></span> </div> <div class="more-right right"> <span class="comments"> </span> </div> </div> </div><!-- article --> <div class="article"> <a class="clearlink" href="15490078791835.html"> <h1>两个数列不等式问题</h1> <div class="a-content"> <div class="a-content-text"> <ol> <li>已知实数 \(x_1, x_2, \dots, x_{10}\), \(\sum\limits_{k=1}^{10} k x_k = 1\). 求 \(\left( \sum\limits_{k=1}^{10} x_k \right)^2 + \sum\limits_{k=1}^{10} x_k^2\) 的最小值.</li> <li>设 \(a_n = 1 + \dfrac12 + \dfrac13 + \dots + \dfrac1n\). 求证: 对 \(n\ge 2\) 有 \(a_n^2 < 2 \left( \dfrac{a_2}2 + \dfrac{a_3}3 + \dots \dfrac{a_n}n \right) + \dfrac{n+3}{2n+2}\).</li> </ol> </div> </div> </a> <div class="read-more clearfix"> <div class="more-left left"> <a href="15490078791835.html">Read more</a> <span class="date">2019/02/01</span> <span>posted in </span> <span class="posted-in"><a href='problemsolving.html'>解题</a></span> </div> <div class="more-right right"> <span class="comments"> </span> </div> </div> </div><!-- article --> <div class="article"> <a class="clearlink" href="15421980305249.html"> <h1>CMO 2018 题 3</h1> <div class="a-content"> <div class="a-content-text"> <p><mark>TODO: 微博图床已挂, 本篇缺图, 需要找回</mark></p> <p>\(\triangle ABC\) 中, \(AB < AC\), \(O\) 为外心, \(D\) 是 \(\angle BAC\) 平分线上一点, \(E\) 在 \(BC\) 上, 满足 \(OE \parallel AD\), \(DE \perp BC\). 在射线 \(EB\) 上取点 \(K\) 满足 \(EK = EA\), \(\triangle ADK\) 外接圆与 \(BC\) 交于另一点 \(P \ne K\), \(\triangle ADK\) 外接圆与 \(\triangle ABC\) 外接圆交于另一点 \(Q \ne A\). 求证: \(PQ\) 与 \(\triangle ABC\) 外接圆相切.</p> </div> </div> </a> <div class="read-more clearfix"> <div class="more-left left"> <a href="15421980305249.html">Read more</a> <span class="date">2018/11/14</span> <span>posted in </span> <span class="posted-in"><a href='problemsolving.html'>解题</a></span> </div> <div class="more-right right"> <span class="comments"> </span> </div> </div> </div><!-- article --> <div class="article"> <a class="clearlink" href="15395877048195.html"> <h1>两个二次函数问题</h1> <div class="a-content"> <div class="a-content-text"> <ol> <li>已知二次函数 \(f(x) = a x^2 + b x + c\) 的图象过点 \((2,8)\), 且对一切实数 \(x\) 恒有 \(2x + 3 \le f(x) \le 2x^2 - 2x + 5\), 求 \(f(x)\).</li> <li>在平面直角坐标系中, 不论 \(m\) 取何值时, 抛物线 \(y = mx^2 + (2m+1) x - (3m+2)\) 都不通过的直线 \(y = -x+1\) 上的点有哪些? (写出全部符合条件点的坐标)</li> </ol> </div> </div> </a> <div class="read-more clearfix"> <div class="more-left left"> <a href="15395877048195.html">Read more</a> <span class="date">2018/10/15</span> <span>posted in </span> <span class="posted-in"><a href='problemsolving.html'>解题</a></span> </div> <div class="more-right right"> <span class="comments"> </span> </div> </div> </div><!-- article --> <div class="article"> <a class="clearlink" href="15348999728702.html"> <h1>伪装成函数方程的数论问题</h1> <div class="a-content"> <div class="a-content-text"> <p>已知函数 \(f(x,y)\) 定义在正整数集上, 满足 \(\forall x,y \in \mathbb N^*\),</p> <ol> <li>\(f(x,x) = x\),</li> <li>\(f(x,y) = f(y,x)\),</li> <li>\((x+y) \cdot f(x,y) = y \cdot f(x, x+y)\).</li> </ol> <p>求证: \(f(x,y) = [x,y]\) (这里, \([x,y]\) 表示 \(x\) 与 \(y\) 的最小公倍数).</p> </div> </div> </a> <div class="read-more clearfix"> <div class="more-left left"> <a href="15348999728702.html">Read more</a> <span class="date">2018/08/22</span> <span>posted in </span> <span class="posted-in"><a href='problemsolving.html'>解题</a></span> </div> <div class="more-right right"> <span class="comments"> </span> </div> </div> </div><!-- article --> <div class="article"> <a class="clearlink" href="15337076183356.html"> <h1>二次根式化简</h1> <div class="a-content"> <div class="a-content-text"> <p>计算:<br/> \[<br/> \dfrac{<br/> 1 + \sqrt{2-\sqrt2} + \sqrt{2-\sqrt3}<br/> }{<br/> \sqrt3 + \sqrt{2+\sqrt2} + \sqrt{2+\sqrt3}<br/> }<br/> \]</p> </div> </div> </a> <div class="read-more clearfix"> <div class="more-left left"> <a href="15337076183356.html">Read more</a> <span class="date">2018/08/08</span> <span>posted in </span> <span class="posted-in"><a href='problemsolving.html'>解题</a></span> </div> <div class="more-right right"> <span class="comments"> </span> </div> </div> </div><!-- article --> <div class="article"> <a class="clearlink" href="15331333919370.html"> <h1>liujihang 20180801</h1> <div class="a-content"> <div class="a-content-text"> <p><mark>TODO: 微博图床已挂, 本篇缺图, 需要找回</mark></p> <p>无穷数列 \(P \colon a_1, a_2, \dots, a_n, \dots\) 满足 \(a_i \in \mathbb N^*\), 且 \(a_i \le a_{i+1}\) (\(i\in \mathbb N^*\)). 对于数列 \(P\), 记 \(T_k (P) = \min \{ n | a_n \ge k \}\) (\(k\in \mathbb N^*\)), 其中 \(\min \{ n | a_n \ge k \}\) 表示集合 \(\{ n | a_n \ge k \}\) 中最小的数.</p> <ol> <li>若数列 \(P\colon 1,3,4,7,\dots\), 写出 \(T_1(P), T_2(P), \dots, T_5(P)\);</li> <li>若 \(T_k (P) = 2k-1\), 求数列 \(P\) 的前 \(n\) 项之和;</li> <li>已知 \(a_{20} = 46\), 求 \(s = a_1 + a_2 + \dots + a_{20} + T_1 (P) + T_2 (P) + \dots + T_{46} (P)\) 的值.</li> </ol> </div> </div> </a> <div class="read-more clearfix"> <div class="more-left left"> <a href="15331333919370.html">Read more</a> <span class="date">2018/08/01</span> <span>posted in </span> <span class="posted-in"><a href='problemsolving.html'>解题</a></span> </div> <div class="more-right right"> <span class="comments"> </span> </div> </div> </div><!-- article --> <div class="article"> <a class="clearlink" href="15327863271008.html"> <h1>不动点为复数值的递推数列问题</h1> <div class="a-content"> <div class="a-content-text"> <p>正数数列 \(\{a_n\}\) 满足 \(S_n + 1 = \dfrac{S_n+4}{2a_n - S_n}\), 其中 \(S_n\) 是 \(\{a_n\}\) 的前 \(n\) 项和, 求 \(\{a_n\}\) 的通项公式.</p> </div> </div> </a> <div class="read-more clearfix"> <div class="more-left left"> <a href="15327863271008.html">Read more</a> <span class="date">2018/07/28</span> <span>posted in </span> <span class="posted-in"><a href='problemsolving.html'>解题</a></span> </div> <div class="more-right right"> <span class="comments"> </span> </div> </div> </div><!-- article --> <div class="article"> <a class="clearlink" href="15288852882913.html"> <h1>三角不等式/极值问题</h1> <div class="a-content"> <div class="a-content-text"> <p><mark>TODO: 本题确认伪证了</mark></p> <p>已知 \(A,B,C\) 为三角形三内角. 求 \(\dfrac{\cos^2 A}{1+\cos A} + \dfrac{\cos^2 B}{1+\cos B} + \dfrac{\cos^2 C}{1+\cos C}\) 的最小值.</p> </div> </div> </a> <div class="read-more clearfix"> <div class="more-left left"> <a href="15288852882913.html">Read more</a> <span class="date">2018/06/13</span> <span>posted in </span> <span class="posted-in"><a href='problemsolving.html'>解题</a></span> </div> <div class="more-right right"> <span class="comments"> </span> </div> </div> </div><!-- article --> <div class="article"> <a class="clearlink" href="15265462412456.html"> <h1>一组高中联赛二试模拟/选拔题 `zhangboxin|20180516`</h1> <div class="a-content"> <div class="a-content-text"> <p><mark>TODO: 微博图床已挂, 本篇缺图, 需要找回</mark></p> <p><mark>TODO: 本篇内容也还没完成</mark></p> <p>这是二试难度的问题 (rdfz 20180516 高联选拔题)</p> </div> </div> </a> <div class="read-more clearfix"> <div class="more-left left"> <a href="15265462412456.html">Read more</a> <span class="date">2018/05/17</span> <span>posted in </span> <span class="posted-in"><a href='problemsolving.html'>解题</a></span> </div> <div class="more-right right"> <span class="comments"> </span> </div> </div> </div><!-- article --> <div class="article"> <a class="clearlink" href="15238569346799.html"> <h1>Poncelet 定理: 圆和抛物线 `zhangboxin|20180409`</h1> <div class="a-content"> <div class="a-content-text"> <p>已知圆 \(C_1 \colon x^2+y^2 = 1\) 和抛物线 \(C_2 \colon y = x^2 - 2\). \(P,Q,R\) 是抛物线 \(C_2\) 上的三个不同的点, 且直线 \(PQ\) 和 \(PR\) 都是圆 \(C_1\) 的切线. 求证: \(QR\) 也是圆 \(C_1\) 的切线.</p> </div> </div> </a> <div class="read-more clearfix"> <div class="more-left left"> <a href="15238569346799.html">Read more</a> <span class="date">2018/04/16</span> <span>posted in </span> <span class="posted-in"><a href='problemsolving.html'>解题</a></span> </div> <div class="more-right right"> <span class="comments"> </span> </div> </div> </div><!-- article --> <div class="article"> <a class="clearlink" href="15166882779923.html"> <h1>平面几何 `duyan|20180123|2`</h1> <div class="a-content"> <div class="a-content-text"> <p><mark>TODO: 微博图床已挂, 本篇缺图, 需要找回</mark></p> <p>已知 \(H\) 为 \(\triangle ABC\) 的垂心, 过 \(H\) 的直线交 \(BC, AB\) 于 \(D,Z\), 过 \(H\) 且垂直于 \(ZH\) 的另一条直线交 \(BC, AC\) 于 \(E,X\), 点 \(Y\) 使得 \(DY \parallel AC, EY \parallel AB\). 求证: \(X,Y,Z\) 三点共线.</p> <p><img src="https://ws2.sinaimg.cn/large/006tKfTcly1fnqjnu4ou9j30iu0h7js7.jpg" alt=""/></p> </div> </div> </a> <div class="read-more clearfix"> <div class="more-left left"> <a href="15166882779923.html">Read more</a> <span class="date">2018/01/23</span> <span>posted in </span> <span class="posted-in"><a href='problemsolving.html'>解题</a></span> </div> <div class="more-right right"> <span class="comments"> </span> </div> </div> </div><!-- article --> <div class="article"> <a class="clearlink" href="15166821516457.html"> <h1>USAMO19xx #5, 高斯函数, 不等式, 第二数学归纳法</h1> <div class="a-content"> <div class="a-content-text"> <p>证明不等式: <br/> \[<br/> [nx] \ge \dfrac{[x]}1 + \dfrac{[2x]}2 + \dfrac{[3x]}3 + \dots +\dfrac{[nx]}n<br/> \]<br/> 其中, \(n \in \mathbb N^*\), \([x]\) 表示不大于 \(x\) 的最大整数.</p> </div> </div> </a> <div class="read-more clearfix"> <div class="more-left left"> <a href="15166821516457.html">Read more</a> <span class="date">2018/01/23</span> <span>posted in </span> <span class="posted-in"><a href='problemsolving.html'>解题</a></span> </div> <div class="more-right right"> <span class="comments"> </span> </div> </div> </div><!-- article --> <div class="article"> <a class="clearlink" href="15166754034002.html"> <h1>一道难度其实不大的平面几何长度计算类证明题 `zhangboxin|20171218`</h1> <div class="a-content"> <div class="a-content-text"> <p><mark>TODO: 微博图床已挂, 本篇缺图, 需要找回</mark></p> <p>在 \(\triangle ABC\) 中, \(\angle A = 4 \angle C\), \(\angle B = 2 \angle C\), 试证: \((BC+CA) \cdot AB = BC \cdot CA\).</p> </div> </div> </a> <div class="read-more clearfix"> <div class="more-left left"> <a href="15166754034002.html">Read more</a> <span class="date">2018/01/23</span> <span>posted in </span> <span class="posted-in"><a href='problemsolving.html'>解题</a></span> </div> <div class="more-right right"> <span class="comments"> </span> </div> </div> </div><!-- article --> <div class="article"> <a class="clearlink" href="15116623932028.html"> <h1>一个常规的递推数列不动点法问题及其引申 `zhangzhiyuan|20171125`</h1> <div class="a-content"> <div class="a-content-text"> <p><mark>TODO: 本文暴露出了我曾经的数学基础的弱点, 需要修改</mark></p> <p>数列 \(\{a_n\}\) 满足 \(a_1 = 2\), \(a_{n+1} = \dfrac{a_n}2 + \dfrac1{a_n}\), 求其通项公式.</p> </div> </div> </a> <div class="read-more clearfix"> <div class="more-left left"> <a href="15116623932028.html">Read more</a> <span class="date">2017/11/26</span> <span>posted in </span> <span class="posted-in"><a href='problemsolving.html'>解题</a></span> </div> <div class="more-right right"> <span class="comments"> </span> </div> </div> </div><!-- article --> <div class="article"> <a class="clearlink" href="15111000681752.html"> <h1>lixinyi 20171119</h1> <div class="a-content"> <div class="a-content-text"> <p>已知函数 \(f(x) = \sqrt{x^2+1}-ax\) (\(a \in \mathbb R\)).</p> <p>(1) 当 \(a=1\) 时, 判断 \(f(x)\) 在 \(\mathbb R\) 上的点调性;<br/> (2) 求实数 \(a\) 的取值范围, 使得函数 \(f(x)\) 在 \(\mathbb R^+\) 上是单调函数.</p> </div> </div> </a> <div class="read-more clearfix"> <div class="more-left left"> <a href="15111000681752.html">Read more</a> <span class="date">2017/11/19</span> <span>posted in </span> <span class="posted-in"><a href='problemsolving.html'>解题</a></span> </div> <div class="more-right right"> <span class="comments"> </span> </div> </div> </div><!-- article --> <div class="article"> <a class="clearlink" href="15107317542032.html"> <h1>libinglun 20171112</h1> <div class="a-content"> <div class="a-content-text"> <p>设 \(p\) 和 \(q\) 是两个质数, 求不能表示为 \(mp + nq\) (其中, \(m,n\) 是自然数) 的最大正整数 (用 \(p\) 和 \(q\) 表示).</p> </div> </div> </a> <div class="read-more clearfix"> <div class="more-left left"> <a href="15107317542032.html">Read more</a> <span class="date">2017/11/15</span> <span>posted in </span> <span class="posted-in"><a href='problemsolving.html'>解题</a></span> </div> <div class="more-right right"> <span class="comments"> </span> </div> </div> </div><!-- article --> <div class="article"> <a class="clearlink" href="15088927359289.html"> <h1>组合极值/组合构造问题 `kongyuqing|20171024`</h1> <div class="a-content"> <div class="a-content-text"> <p>100 个数围成一圈, \(a_{3} > a_{2} + a_{1}\), \(a_{4} > a_{3} + a_{2}\), \(\dots\) , \(a_{100} > a_{99} + a_{98}\), \(a_{1} > a_{100} + a_{99}\), \(a_{2} > a_{1} + a_{100}\), 问其中最多有多少个正数?</p> </div> </div> </a> <div class="read-more clearfix"> <div class="more-left left"> <a href="15088927359289.html">Read more</a> <span class="date">2017/10/25</span> <span>posted in </span> <span class="posted-in"><a href='problemsolving.html'>解题</a></span> </div> <div class="more-right right"> <span class="comments"> </span> </div> </div> </div><!-- article --> <div class="article"> <a class="clearlink" href="15078172804643.html"> <h1>递推数列推出组合数的问题 `duyan@bj#4|20171012`</h1> <div class="a-content"> <div class="a-content-text"> <p>已知 \(S_n\) 为数列 \(\{a_n\}\) 的前 \(n\) 项和, 规定 \(S_0 = 0\), 若对任意 \(n \in \mathbb N^*\), 均有 \(\dfrac{a_n}{2017} = - \dfrac{2017+S_{n-1}}{n}\), 则 \(\sum\limits_{n=1}^{2017} 2^n a_n = \) <code>______</code>.</p> </div> </div> </a> <div class="read-more clearfix"> <div class="more-left left"> <a href="15078172804643.html">Read more</a> <span class="date">2017/10/12</span> <span>posted in </span> <span class="posted-in"><a href='problemsolving.html'>解题</a></span> </div> <div class="more-right right"> <span class="comments"> </span> </div> </div> </div><!-- article --> <div class="article"> <a class="clearlink" href="15075145910644.html"> <h1>三圆轮换对称不等式问题 `mawentao|20170914`</h1> <div class="a-content"> <div class="a-content-text"> <p><code>问题</code> \(a,b,c \ge 0\), 求证:<br/> \[<br/> \begin{aligned}<br/> &\sqrt{a^2 - ab + b^2} \cdot \sqrt{b^2 - bc + c^2} \\<br/> &{}+ \sqrt{b^2 - bc + c^2} \cdot \sqrt{c^2 - ca + a^2} \\<br/> &{}+ \sqrt{c^2 - ca + a^2} \cdot \sqrt{a^2 - ab + b^2}<br/> \ge a^2 + b^2 + c^2<br/> \end{aligned}<br/> \]</p> </div> </div> </a> <div class="read-more clearfix"> <div class="more-left left"> <a href="15075145910644.html">Read more</a> <span class="date">2017/10/09</span> <span>posted in </span> 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