{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "This notebook was prepared by [Donne Martin](https://github.com/donnemartin). Source and license info is on [GitHub](https://github.com/donnemartin/interactive-coding-challenges)." ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "# Solution Notebook" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Problem: Check if a number is prime.\n", "\n", "* [Constraints](#Constraints)\n", "* [Test Cases](#Test-Cases)\n", "* [Algorithm](#Algorithm)\n", "* [Code](#Code)\n", "* [Unit Test](#Unit-Test)" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Constraints\n", "\n", "* Is it correct that 1 is not considered a prime number?\n", " * Yes\n", "* Can we assume the inputs are valid?\n", " * No\n", "* Can we assume this fits memory?\n", " * Yes" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Test Cases\n", "\n", "* None -> Exception\n", "* Not an int -> Exception\n", "* Less than 2 -> False\n", "* General case" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Algorithm\n", "\n", "For a number to be prime, it must be 2 or greater and cannot be divisible by another number other than itself (and 1).\n", "\n", "We'll check by dividing all numbers from 2 to the input number to determine if the number is prime.\n", "\n", "As an optimization, we can divide from 2 to the square root of the input number. For each value that divides the input number evenly, there is a complement b where a * b = n. If a > sqrt(n) then b < sqrt(n) because sqrt(n^2) = n.\n", "\n", "Complexity:\n", "* Time: O(n) where n is the value of the input number\n", "* Space: O(1)\n", "\n", "### Sieve of Eratosthenes\n", "\n", "The Sieve of Eratosthenes provides a more efficient way of computing and generating primes. See the challenge [\"Generate a list of primes\"]() for more details." ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Code" ] }, { "cell_type": "code", "execution_count": 1, "metadata": {}, "outputs": [], "source": [ "import math\n", "\n", "\n", "class Math(object):\n", "\n", " def check_prime(self, num):\n", " if num is None:\n", " raise TypeError('num cannot be None')\n", " if num < 2:\n", " return False\n", " for i in range(2, num):\n", " if num % i == 0:\n", " return False\n", " return True\n", "\n", " def check_prime_optimized(self, num):\n", " if num is None:\n", " raise TypeError('num cannot be None')\n", " if num < 2:\n", " return False\n", " for i in range(2, int(math.sqrt(num)+1)):\n", " if num % i == 0:\n", " return False\n", " return True" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Unit Test" ] }, { "cell_type": "code", "execution_count": 2, "metadata": {}, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "Overwriting test_check_prime.py\n" ] } ], "source": [ "%%writefile test_check_prime.py\n", "import unittest\n", "\n", "\n", "class TestMath(unittest.TestCase):\n", "\n", " def test_check_prime(self):\n", " math = Math()\n", " self.assertRaises(TypeError, math.check_prime, None)\n", " self.assertRaises(TypeError, math.check_prime, 98.6)\n", " self.assertEqual(math.check_prime(0), False)\n", " self.assertEqual(math.check_prime(1), False)\n", " self.assertEqual(math.check_prime(97), True)\n", " print('Success: test_check_prime')\n", "\n", "\n", "def main():\n", " test = TestMath()\n", " test.test_check_prime()\n", "\n", "\n", "if __name__ == '__main__':\n", " main()" ] }, { "cell_type": "code", "execution_count": 3, "metadata": {}, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "Success: test_check_prime\n" ] } ], "source": [ "%run -i test_check_prime.py" ] } ], "metadata": { "kernelspec": { "display_name": "Python 3", "language": "python", "name": "python3" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 3 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython3", "version": "3.7.2" } }, "nbformat": 4, "nbformat_minor": 1 }