{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "This notebook was prepared by [Donne Martin](http://donnemartin.com). Source and license info is on [GitHub](https://github.com/donnemartin/interactive-coding-challenges)." ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "# Challenge Notebook" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Problem: Implement a function to reverse a string (a list of characters), in-place.\n", "\n", "* [Constraints](#Constraints)\n", "* [Test Cases](#Test-Cases)\n", "* [Algorithm](#Algorithm)\n", "* [Code](#Code)\n", "* [Unit Test](#Unit-Test)\n", "* [Solution Notebook](#Solution-Notebook)" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Constraints\n", "\n", "* Can we assume the string is ASCII?\n", " * Yes\n", " * Note: Unicode strings could require special handling depending on your language\n", "* Since we need to do this in-place, it seems we cannot use the slice operator or the reversed function?\n", " * Correct\n", "* Since Python string are immutable, can we use a list of characters instead?\n", " * Yes" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Test Cases\n", "\n", "* None -> None\n", "* [''] -> ['']\n", "* ['f', 'o', 'o', ' ', 'b', 'a', 'r'] -> ['r', 'a', 'b', ' ', 'o', 'o', 'f']" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Algorithm\n", "\n", "Refer to the [Solution Notebook](http://nbviewer.ipython.org/github/donnemartin/interactive-coding-challenges/blob/master/arrays_strings/reverse_string/reverse_string_solution.ipynb). If you are stuck and need a hint, the solution notebook's algorithm discussion might be a good place to start." ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Code" ] }, { "cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": [ "class ReverseString(object):\n", "\n", " def reverse(self, chars):\n", " # TODO: Implement me\n", " pass" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Unit Test" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "\n", "\n", "**The following unit test is expected to fail until you solve the challenge.**" ] }, { "cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": [ "# %load test_reverse_string.py\n", "import unittest\n", "\n", "\n", "class TestReverse(unittest.TestCase):\n", "\n", " def test_reverse(self, func):\n", " self.assertEqual(func(None), None)\n", " self.assertEqual(func(['']), [''])\n", " self.assertEqual(func(\n", " ['f', 'o', 'o', ' ', 'b', 'a', 'r']),\n", " ['r', 'a', 'b', ' ', 'o', 'o', 'f'])\n", " print('Success: test_reverse')\n", "\n", " def test_reverse_inplace(self, func):\n", " target_list = ['f', 'o', 'o', ' ', 'b', 'a', 'r']\n", " func(target_list)\n", " self.assertEqual(target_list, ['r', 'a', 'b', ' ', 'o', 'o', 'f'])\n", " print('Success: test_reverse_inplace')\n", "\n", "\n", "def main():\n", " test = TestReverse()\n", " reverse_string = ReverseString()\n", " test.test_reverse(reverse_string.reverse)\n", " test.test_reverse_inplace(reverse_string.reverse)\n", "\n", "\n", "if __name__ == '__main__':\n", " main()" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Solution Notebook\n", "\n", "Review the [Solution Notebook](http://nbviewer.ipython.org/github/donnemartin/interactive-coding-challenges/blob/master/arrays_strings/reverse_string/reverse_string_solution.ipynb) for a discussion on algorithms and code solutions." ] } ], "metadata": { "kernelspec": { "display_name": "Python 3", "language": "python", "name": "python3" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 3 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython3", "version": "3.7.2" } }, "nbformat": 4, "nbformat_minor": 1 }