(* Un_numero_es_par_syss_lo_es_su_cuadrado.lean -- Un número es par si y solo si lo es su cuadrado -- José A. Alonso Jiménez -- Sevilla, 27-mayo-2024 -- ------------------------------------------------------------------ *) (* --------------------------------------------------------------------- -- Demostrar que un número es par si y solo si lo es su cuadrado. -- ------------------------------------------------------------------ *) theory Un_numero_es_par_syss_lo_es_su_cuadrado imports Main begin (* 1\ demostración *) lemma fixes n :: int shows "even (n\<^sup>2) \ even n" proof (rule iffI) assume "even (n\<^sup>2)" show "even n" proof (rule ccontr) assume "odd n" then obtain k where "n = 2*k+1" by (rule oddE) then have "n\<^sup>2 = 2*(2*k*(k+1))+1" proof - have "n\<^sup>2 = (2*k+1)\<^sup>2" by (simp add: \n = 2 * k + 1\) also have "\ = 4*k\<^sup>2+4*k+1" by algebra also have "\ = 2*(2*k*(k+1))+1" by algebra finally show "n\<^sup>2 = 2*(2*k*(k+1))+1" . qed then have "\k'. n\<^sup>2 = 2*k'+1" by (rule exI) then have "odd (n\<^sup>2)" by fastforce then show False using \even (n\<^sup>2)\ by blast qed next assume "even n" then obtain k where "n = 2*k" by (rule evenE) then have "n\<^sup>2 = 2*(2*k\<^sup>2)" by simp then show "even (n\<^sup>2)" by simp qed (* 2\ demostración *) lemma fixes n :: int shows "even (n\<^sup>2) \ even n" proof assume "even (n\<^sup>2)" show "even n" proof (rule ccontr) assume "odd n" then obtain k where "n = 2*k+1" by (rule oddE) then have "n\<^sup>2 = 2*(2*k*(k+1))+1" by algebra then have "odd (n\<^sup>2)" by simp then show False using \even (n\<^sup>2)\ by blast qed next assume "even n" then obtain k where "n = 2*k" by (rule evenE) then have "n\<^sup>2 = 2*(2*k\<^sup>2)" by simp then show "even (n\<^sup>2)" by simp qed (* 3\ demostración *) lemma fixes n :: int shows "even (n\<^sup>2) \ even n" proof - have "even (n\<^sup>2) = (even n \ (0::nat) < 2)" by (simp only: even_power) also have "\ = (even n \ True)" by (simp only: less_numeral_simps) also have "\ = even n" by (simp only: HOL.simp_thms(21)) finally show "even (n\<^sup>2) \ even n" by this qed (* 4\ demostración *) lemma fixes n :: int shows "even (n\<^sup>2) \ even n" proof - have "even (n\<^sup>2) = (even n \ (0::nat) < 2)" by (simp only: even_power) also have "\ = even n" by simp finally show "even (n\<^sup>2) \ even n" . qed (* 5\ demostración *) lemma fixes n :: int shows "even (n\<^sup>2) \ even n" by simp end