{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "# 1. Creating formulas\n", "Write the following mathematical formula in Python:\n", "\n", "\\begin{align}\n", " result = 6a^3 - \\frac{8b^2 }{4c} + 11\n", "\\end{align}\n" ] }, { "cell_type": "code", "execution_count": null, "metadata": { "editable": false }, "outputs": [], "source": [ "a = 2\n", "b = 3\n", "c = 2" ] }, { "cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": [ "# Your formula here:\n", "result = " ] }, { "cell_type": "code", "execution_count": null, "metadata": { "editable": false }, "outputs": [], "source": [ "\n", "assert result == 50" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "# 2. Floating point pitfalls\n", "Show that 0.1 + 0.2 == 0.3" ] }, { "cell_type": "code", "execution_count": 4, "metadata": {}, "outputs": [], "source": [ "# Your solution here\n", "\n", "# This won't work:\n", "# assert 0.1 + 0.2 == 0.3" ] } ], "metadata": { "kernelspec": { "display_name": "Python 3", "language": "python", "name": "python3" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 3 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython3", "version": "3.5.4" } }, "nbformat": 4, "nbformat_minor": 2 }