{
 "metadata": {
  "name": "sho1d_example"
 },
 "nbformat": 3,
 "nbformat_minor": 0,
 "worksheets": [
  {
   "cells": [
    {
     "cell_type": "heading",
     "level": 1,
     "metadata": {},
     "source": [
      "Example Notebook for sho1d.py"
     ]
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "Import the sho1d.py file as well as the test_sho1d.py file"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "%load_ext sympy.interactive.ipythonprinting \n",
      "from sympy import *\n",
      "from IPython.display import display_pretty\n",
      "from sympy.physics.quantum import *\n",
      "from sympy.physics.quantum.sho1d import *\n",
      "from sympy.physics.quantum.tests.test_sho1d import *"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "The sympy.interactive.ipythonprinting extension is already loaded. To reload it, use:\n",
        "  %reload_ext sympy.interactive.ipythonprinting\n"
       ]
      }
     ],
     "prompt_number": 1
    },
    {
     "cell_type": "heading",
     "level": 3,
     "metadata": {},
     "source": [
      "Printing Of Operators"
     ]
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "Create a raising and lowering operator and make sure they print correctly"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "ad = RaisingOp('a')\n",
      "a = LoweringOp('a')"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [],
     "prompt_number": 2
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "ad"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 3,
       "text": [
        "RaisingOp(a)"
       ]
      }
     ],
     "prompt_number": 3
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "a"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 4,
       "text": [
        "a"
       ]
      }
     ],
     "prompt_number": 4
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "print latex(ad)\n",
      "print latex(a)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "a^{\\dag}\n",
        "a\n"
       ]
      }
     ],
     "prompt_number": 5
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "display_pretty(ad)\n",
      "display_pretty(a)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "display_data",
       "text": [
        "RaisingOp(a)"
       ]
      },
      {
       "output_type": "display_data",
       "text": [
        "a"
       ]
      }
     ],
     "prompt_number": 6
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "print srepr(ad)\n",
      "print srepr(a)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "RaisingOp(Symbol('a'))\n",
        "LoweringOp(Symbol('a'))\n"
       ]
      }
     ],
     "prompt_number": 7
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "print repr(ad)\n",
      "print repr(a)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "RaisingOp(a)\n",
        "a\n"
       ]
      }
     ],
     "prompt_number": 8
    },
    {
     "cell_type": "heading",
     "level": 3,
     "metadata": {},
     "source": [
      "Printing of States"
     ]
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "Create a simple harmonic state and check its printing"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "k = SHOKet('k')\n",
      "b = SHOBra('b')"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [],
     "prompt_number": 9
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "k"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 10,
       "text": [
        "|k>"
       ]
      }
     ],
     "prompt_number": 10
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "b"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 11,
       "text": [
        "<b|"
       ]
      }
     ],
     "prompt_number": 11
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "print pretty(k)\n",
      "print pretty(b)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "\u2758k\u27e9\n",
        "\u27e8b\u2758\n"
       ]
      }
     ],
     "prompt_number": 12
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "print latex(k)\n",
      "print latex(b)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "{\\left|k\\right\\rangle }\n",
        "{\\left\\langle b\\right|}\n"
       ]
      }
     ],
     "prompt_number": 13
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "print srepr(k)\n",
      "print srepr(b)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "SHOKet(Symbol('k'))\n",
        "SHOBra(Symbol('b'))\n"
       ]
      }
     ],
     "prompt_number": 14
    },
    {
     "cell_type": "heading",
     "level": 3,
     "metadata": {},
     "source": [
      "Properties"
     ]
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "Take the dagger of the raising and lowering operators. They should return eachother."
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "Dagger(ad)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 15,
       "text": [
        "a"
       ]
      }
     ],
     "prompt_number": 15
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "Dagger(a)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 16,
       "text": [
        "RaisingOp(a)"
       ]
      }
     ],
     "prompt_number": 16
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "Check Commutators of the raising and lowering operators"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "Commutator(ad,a).doit()"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 17,
       "text": [
        "-1"
       ]
      }
     ],
     "prompt_number": 17
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "Commutator(a,ad).doit()"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 18,
       "text": [
        "1"
       ]
      }
     ],
     "prompt_number": 18
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "Take a look at the dual states of the bra and ket"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "k.dual"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 19,
       "text": [
        "<k|"
       ]
      }
     ],
     "prompt_number": 19
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "b.dual"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 20,
       "text": [
        "|b>"
       ]
      }
     ],
     "prompt_number": 20
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "Taking the InnerProduct of the bra and ket will return the KroneckerDelta function"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "InnerProduct(b,k).doit()"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 21,
       "text": [
        "KroneckerDelta(k, b)"
       ]
      }
     ],
     "prompt_number": 21
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "Take a look at how the raising and lowering operators act on states. We use qapply to apply an operator to a state"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "qapply(ad*k)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 22,
       "text": [
        "sqrt(k + 1)*|k + 1>"
       ]
      }
     ],
     "prompt_number": 22
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "qapply(a*k)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 23,
       "text": [
        "sqrt(k)*|k - 1>"
       ]
      }
     ],
     "prompt_number": 23
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "But the states may have an explicit energy level. Let's look at the ground and first excited states"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "kg = SHOKet(0)\n",
      "kf = SHOKet(1)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [],
     "prompt_number": 24
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "qapply(ad*kg)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 25,
       "text": [
        "|1>"
       ]
      }
     ],
     "prompt_number": 25
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "qapply(ad*kf)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 26,
       "text": [
        "sqrt(2)*|2>"
       ]
      }
     ],
     "prompt_number": 26
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "qapply(a*kg)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 27,
       "text": [
        "0"
       ]
      }
     ],
     "prompt_number": 27
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "qapply(a*kf)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 28,
       "text": [
        "|0>"
       ]
      }
     ],
     "prompt_number": 28
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "Notice that a*kg is 0 and a*kf is the |0> the ground state."
     ]
    },
    {
     "cell_type": "heading",
     "level": 3,
     "metadata": {},
     "source": [
      "NumberOp & Hamiltonian"
     ]
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "Let's look at the Number Operator and Hamiltonian Operator"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "k = SHOKet('k')\n",
      "ad = RaisingOp('a')\n",
      "a = LoweringOp('a')\n",
      "N = NumberOp('N')\n",
      "H = Hamiltonian('H')"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [],
     "prompt_number": 29
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "The number operator is simply expressed as ad*a"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "N().rewrite('a').doit()"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 30,
       "text": [
        "RaisingOp(a)*a"
       ]
      }
     ],
     "prompt_number": 30
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "The number operator expressed in terms of the position and momentum operators"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "N().rewrite('xp').doit()"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 31,
       "text": [
        "-1/2 + (m**2*omega**2*X**2 + Px**2)/(2*hbar*m*omega)"
       ]
      }
     ],
     "prompt_number": 31
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "It can also be expressed in terms of the Hamiltonian operator"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "N().rewrite('H').doit()"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 32,
       "text": [
        "-1/2 + H/(hbar*omega)"
       ]
      }
     ],
     "prompt_number": 32
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "The Hamiltonian operator can be expressed in terms of the raising and lowering operators, position and momentum operators, and the number operator"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "H().rewrite('a').doit()"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 33,
       "text": [
        "hbar*omega*(1/2 + RaisingOp(a)*a)"
       ]
      }
     ],
     "prompt_number": 33
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "H().rewrite('xp').doit()"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 34,
       "text": [
        "(m**2*omega**2*X**2 + Px**2)/(2*m)"
       ]
      }
     ],
     "prompt_number": 34
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "H().rewrite('N').doit()"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 35,
       "text": [
        "hbar*omega*(1/2 + N)"
       ]
      }
     ],
     "prompt_number": 35
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "The raising and lowering operators can also be expressed in terms of the position and momentum operators"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "ad().rewrite('xp').doit()"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 36,
       "text": [
        "sqrt(2)*(m*omega*X - I*Px)/(2*sqrt(hbar)*sqrt(m*omega))"
       ]
      }
     ],
     "prompt_number": 36
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "a().rewrite('xp').doit()"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 37,
       "text": [
        "sqrt(2)*(m*omega*X + I*Px)/(2*sqrt(hbar)*sqrt(m*omega))"
       ]
      }
     ],
     "prompt_number": 37
    },
    {
     "cell_type": "heading",
     "level": 3,
     "metadata": {},
     "source": [
      "Properties"
     ]
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "Let's take a look at how the NumberOp and Hamiltonian act on states"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "qapply(N*k)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 38,
       "text": [
        "k*|k>"
       ]
      }
     ],
     "prompt_number": 38
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "Apply the Number operator to a state returns the state times the ket"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "ks = SHOKet(2)\n",
      "qapply(N*ks)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 39,
       "text": [
        "2*|2>"
       ]
      }
     ],
     "prompt_number": 39
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "qapply(H*k)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 40,
       "text": [
        "hbar*k*omega*|k> + hbar*omega*|k>/2"
       ]
      }
     ],
     "prompt_number": 40
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "Let's see how the operators commute with each other"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "Commutator(N,ad).doit()"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 41,
       "text": [
        "RaisingOp(a)"
       ]
      }
     ],
     "prompt_number": 41
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "Commutator(N,a).doit()"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 42,
       "text": [
        "-a"
       ]
      }
     ],
     "prompt_number": 42
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "Commutator(N,H).doit()"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 43,
       "text": [
        "0"
       ]
      }
     ],
     "prompt_number": 43
    },
    {
     "cell_type": "heading",
     "level": 3,
     "metadata": {},
     "source": [
      "Representation"
     ]
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "We can express the operators in NumberOp basis. There are different ways to create a matrix in Python, we will use 3 different ways."
     ]
    },
    {
     "cell_type": "heading",
     "level": 4,
     "metadata": {},
     "source": [
      "Sympy"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "represent(ad, basis=N, ndim=4, format='sympy')"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 44,
       "text": [
        "[0,       0,       0, 0]\n",
        "[1,       0,       0, 0]\n",
        "[0, sqrt(2),       0, 0]\n",
        "[0,       0, sqrt(3), 0]"
       ]
      }
     ],
     "prompt_number": 44
    },
    {
     "cell_type": "heading",
     "level": 4,
     "metadata": {},
     "source": [
      "Numpy"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "represent(ad, basis=N, ndim=5, format='numpy')"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 45,
       "text": [
        "array([[ 0.        ,  0.        ,  0.        ,  0.        ,  0.        ],\n",
        "       [ 1.        ,  0.        ,  0.        ,  0.        ,  0.        ],\n",
        "       [ 0.        ,  1.41421356,  0.        ,  0.        ,  0.        ],\n",
        "       [ 0.        ,  0.        ,  1.73205081,  0.        ,  0.        ],\n",
        "       [ 0.        ,  0.        ,  0.        ,  2.        ,  0.        ]])"
       ]
      }
     ],
     "prompt_number": 45
    },
    {
     "cell_type": "heading",
     "level": 4,
     "metadata": {},
     "source": [
      "Scipy.Sparse"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "represent(ad, basis=N, ndim=4, format='scipy.sparse', spmatrix='lil')"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 46,
       "text": [
        "<4x4 sparse matrix of type '<type 'numpy.float64'>'\n",
        "\twith 3 stored elements in Compressed Sparse Row format>"
       ]
      }
     ],
     "prompt_number": 46
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "print represent(ad, basis=N, ndim=4, format='scipy.sparse', spmatrix='lil')"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "  (1, 0)\t1.0\n",
        "  (2, 1)\t1.41421356237\n",
        "  (3, 2)\t1.73205080757\n"
       ]
      }
     ],
     "prompt_number": 47
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "The same can be done for the other operators"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "represent(a, basis=N, ndim=4, format='sympy')"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 48,
       "text": [
        "[0, 1,       0,       0]\n",
        "[0, 0, sqrt(2),       0]\n",
        "[0, 0,       0, sqrt(3)]\n",
        "[0, 0,       0,       0]"
       ]
      }
     ],
     "prompt_number": 48
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "represent(N, basis=N, ndim=4, format='sympy')"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 49,
       "text": [
        "[0, 0, 0, 0]\n",
        "[0, 1, 0, 0]\n",
        "[0, 0, 2, 0]\n",
        "[0, 0, 0, 3]"
       ]
      }
     ],
     "prompt_number": 49
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "represent(H, basis=N, ndim=4, format='sympy')"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "pyout",
       "prompt_number": 50,
       "text": [
        "[hbar*omega/2,              0,              0,              0]\n",
        "[           0, 3*hbar*omega/2,              0,              0]\n",
        "[           0,              0, 5*hbar*omega/2,              0]\n",
        "[           0,              0,              0, 7*hbar*omega/2]"
       ]
      }
     ],
     "prompt_number": 50
    },
    {
     "cell_type": "heading",
     "level": 4,
     "metadata": {},
     "source": [
      "Ket and Bra Representation"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "k0 = SHOKet(0)\n",
      "k1 = SHOKet(1)\n",
      "b0 = SHOBra(0)\n",
      "b1 = SHOBra(1)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [],
     "prompt_number": 51
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "print represent(k0, basis=N, ndim=5, format='sympy')"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "[1]\n",
        "[0]\n",
        "[0]\n",
        "[0]\n",
        "[0]\n"
       ]
      }
     ],
     "prompt_number": 52
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "print represent(k1, basis=N, ndim=5, format='sympy')"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "[0]\n",
        "[1]\n",
        "[0]\n",
        "[0]\n",
        "[0]\n"
       ]
      }
     ],
     "prompt_number": 53
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "print represent(b0, basis=N, ndim=5, format='sympy')"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "[1, 0, 0, 0, 0]\n"
       ]
      }
     ],
     "prompt_number": 54
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "print represent(b1, basis=N, ndim=5, format='sympy')"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "[0, 1, 0, 0, 0]\n"
       ]
      }
     ],
     "prompt_number": 55
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [],
     "language": "python",
     "metadata": {},
     "outputs": []
    }
   ],
   "metadata": {}
  }
 ]
}