function value = p28_f ( dim_num, point_num, x ) %*****************************************************************************80 % %% P28_F evaluates the integrand for problem 28. % % Dimension: % % N arbitrary. % % Region: % % 0 <= X(1:DIM_NUM) <= 1 % % Integral Parameters: % % The integral depends on vectors C(1:N) and Z(1:N). % To get or set C or Z, call P28_R8VEC. % % The reference suggests choosing C by initializing % it to random values in [0,1], and then normalizing so that % % sum ( 1/C(1:N)**2 ) = 170 / N**(7/2) % % C(1:N) used to default to N**(9/4) / sqrt(170) % but this is INSUPPORTABLE for large dimension N. % % So now we're setting C(1:N) to default to 1.0 % % The reference suggests choosing Z at random in [0,1]. % % Z(1:N) defaults to 0.5. % % Integrand: % % 1 / product ( C(1:DIM_NUM)**2 + ( X(1:DIM_NUM) - Z(1:DIM_NUM) )**2 ) % % Exact Integral: % % product ( ( arctan ( ( 1 - Z(1:DIM_NUM) ) / C(1:DIM_NUM) ) % + arctan ( Z(1:DIM_NUM) / C(1:DIM_NUM) ) % ) / C(1:DIM_NUM) % ) % % Licensing: % % This code is distributed under the GNU LGPL license. % % Modified: % % 02 June 2007 % % Author: % % John Burkardt % % Reference: % % Alan Genz, % [Integral #2] % A Package for Testing Multiple Integration Subroutines, % in Numerical Integration: Recent Developments, Software % and Applications, % edited by Patrick Keast and Graeme Fairweather, % D Reidel, 1987, pages 337-340, % LC: QA299.3.N38. % % Thomas Patterson, % [Integral #6], % On the Construction of a Practical Ermakov-Zolotukhin % Multiple Integrator, % in Numerical Integration: Recent Developments, Software % and Applications, % edited by Patrick Keast and Graeme Fairweather, % D. Reidel, 1987, pages 269-290, % LC: QA299.3.N38. % % Parameters: % % Input, integer DIM_NUM, the dimension of the argument. % % Input, integer POINT_NUM, the number of points. % % Input, real X(DIM_NUM,POINT_NUM), the evaluation points. % % Output, real VALUE(POINT_NUM), the integrand values. % c = []; c = p28_r8vec ( 'G', 'C', dim_num, c ); z = []; z = p28_r8vec ( 'G', 'Z', dim_num, z ); value(1:point_num) = 0.0; for point = 1 : point_num value(point) = 1.0 / prod ( c(1:dim_num)'.^2 ... + ( x(1:dim_num,point) - z(1:dim_num)' ).^2 ); end p28_i4 ( 'I', '#', point_num ); return end