{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "# 2.3 单位矩阵和逆" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "### 单位矩阵" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "为了引入矩阵的逆,我们需要先定义单位矩阵:单位矩阵乘以任意一个向量等于这个向量本身。记 $\\mathbf I_n$ 为保持 $n$ 维向量不变的单位矩阵,即:\n", "\n", "$$\n", "\\mathbf I_n \\in \\mathbb R^{n\\times n}, \\forall \\mathbf x \\in \\mathbb R^{n}, \\mathbf I_n \\mathbf{x=x}\n", "$$\n", "\n", "单位矩阵的形式十分简单,所有的对角元素都为 $1$,其他元素都为 $0$,如:\n", "\n", "$$\n", "\\mathbf I_3\n", "\\begin{bmatrix}\n", "1 & 0 & 0 \\\\\n", "0 & 1 & 0 \\\\\n", "0 & 0 & 1 \\\\\n", "\\end{bmatrix}\n", "$$" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "### 矩阵的逆 " ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "矩阵 $\\bf A$ 的逆记作 $\\mathbf A^{-1}$,定义为一个矩阵使得\n", "\n", "$$\n", "\\mathbf A^{-1} \\mathbf A = \\mathbf I_n\n", "$$\n", "\n", "如果 $\\mathbf A^{-1}$ 存在,那么线性方程组 $\\bf Ax=b$ 的解为:\n", "\n", "$$\n", "\\mathbf A^{-1}\\mathbf{Ax} = \\mathbf I_n \\mathbf x = \\mathbf x = \\mathbf A^{-1}\\mathbf b\n", "$$" ] } ], "metadata": { "kernelspec": { "display_name": "Python 2", "language": "python", "name": "python2" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 2 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython2", "version": "2.7.6" } }, "nbformat": 4, "nbformat_minor": 0 }