val numbers = arrayOf(1, 2, 3)
val letters = listOf("a", "b", "c")
// 将两个数组的元素按顺序配对,配对后的元素: [(1, a), (2, b), (3, c)]
numbers.zip(letters) { o1, o2 -> o1 to o2 }.forEach {
    _console.log(it)
}