{ "metadata": { "name": "", "signature": "sha256:8b4d34a93f910c7af708b7e5c47e41b8974dd426a937d1a9162cb3941bb48c55" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "# Ortogonaliza\u00e7\u00e3o\n", "\n", "Seja $T =\\{ (x_0,y_0),\\dots, (x_k,y_k)\\}$ uma tabela regular e $\\{g_0,\\dots,g_n\\}$ uma fam\u00edlia de fun\u00e7\u00f5es reais. Dizemos que a fam\u00edlia \u00e9 ortogonal em rela\u00e7\u00e3o \u00e0 tabela dada se $\\langle g_i,g_j\\rangle=0$ para $i\\neq j$ e $\\langle g_i,g_i\\rangle>0$. Lembro a defini\u00e7\u00e3o $\\langle g_i,g_j\\rangle=\\sum_{l=0}^k g_i(x_l)g_k(x_l)$.\n", "\n", "Neste caso a solu\u00e7\u00e3o do problema de MMQ \u00e9 $a_i = \\frac{\\langle g_i,y \\rangle}{\\langle g_i,g_i\\rangle}$." ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Gram-Schmidt aqui.\n", "Se a fam\u00edlia $\\mathbb{G} = \\{g_0,\\dots,g_n\\}$ n\u00e3o \u00e9 ortogonal e vale que $\\langle g_i,g_i\\rangle>0$, ent\u00e3o podemos definir\n", "$$ \\begin{eqnarray}\n", "f_0 &= &g_0\\\\\n", "f_j & = & g_j - \\sum_{i=1}^{j-1}\\frac{\\langle g_j,f_i\\rangle}{\\langle f_i,f_i\\rangle}f_i\n", "\\end{eqnarray}\n", "$$\n", "\n", "Agora a fam\u00edlia de fun\u00e7\u00f5es $\\mathbb{F} = \\{f_0,\\dots,f_n\\}$ gera o mesmo espa\u00e7o de fun\u00e7\u00f5es que a fam\u00edlia $\\mathbb{G}$ e esta fam\u00edlia \u00e9 ortogonal em rela\u00e7\u00e3o \u00e0 tabela $T$." ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "### Prova\n", "Primeiro mostramos que $f_0$ e $f_1$ s\u00e3o ortogonais. Da defini\u00e7\u00e3o temos que $f_1 = g_1 - \\frac{\\langle g_1, g_0\\rangle}{ \\langle g_0, g_0\\rangle}g_0$. Usando as propriedades de bilinearidade do produto interno temos que $\\langle f_1, f_0\\rangle =0$.\n", "\n", "No segundo passo, assumimos que o conjunto $\\{f_0,\\dots,f_{i-1}\\}$ \u00e9 ortogonal ent\u00e3o $\\{f_0,\\dots,f_{i}\\}$ \u00e9 ortogonal. De fato basta mostrar que $\\langle f_i, f_j\\rangle =0$ para $j\\lt i$. Temos ent\u00e3o:\n", "$$\\langle f_i, f_j\\rangle = \\langle g_i - \\sum_{l=1}^{i-1}\\frac{\\langle g_i,f_l\\rangle}{\\langle f_l,f_l\\rangle}f_l , f_j\\rangle = \\langle g_i, f_j \\rangle - \\sum_{l=1}^{i-1}\\frac{\\langle g_i,f_l\\rangle}{\\langle f_l,f_l\\rangle}\\langle f_l , f_j\\rangle =0$$" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "#### Exemplo\n", "* $T=\\{ (0,-1), (1,2), (2,0)\\}$ \n", "* $\\mathbb{G} =\\{ g_0(x)=1, g_1(x)=x\\}$\n", "* $P_g=\\begin{pmatrix} 1 & 1 & 1 \\\\ 0 & 1 & 2\\end{pmatrix}$\n", "* $f_0(x)=1$\n", "* $f_1(x) = x - 1$\n", "* $P_f=\\begin{pmatrix} 1 & 1 & 1 \\\\ -1 & 0 & 1\\end{pmatrix}$" ] }, { "cell_type": "code", "collapsed": false, "input": [], "language": "python", "metadata": {}, "outputs": [] } ], "metadata": {} } ] }