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   "source": [
    "# Functions - Exercises"
   ]
  },
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   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Exercise 4.1.\n",
    "\n",
    "In a given university course, the final grade is determined by grade for essay and by the grade for a presentation. The presentation counts for 30% and the essay for 70%. Write two functions: (1) one function which can calculate the final grade based on a set of partial grades. Grades must be rounded to integers. 5.4, for example, becomes 5 and 6.6 becomes 7. (2) Write a second function which can determine whether a given grade is at a pass level (i.e. higher than 6). This function must return a boolean value, in which 'pass' is true and 'fail' equals false.    "
   ]
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   "source": [
    "def calculateMark( essay, presentation ):\n",
    "    partial1 = essay * 0.7\n",
    "    partial2 = presentation * 0.3\n",
    "    final = partial1 + partial2\n",
    "    return round(final)\n",
    "\n",
    "def isPass(grade):\n",
    "    eval = 'Fail'\n",
    "    if grade > 6:\n",
    "        eval = 'Pass'\n",
    "    return eval\n",
    "        \n",
    "\n",
    "essay = 7.0\n",
    "presentation = 8.5\n",
    "final = calculateMark(essay,presentation)\n",
    "print( \"final grade: {} ({})\".format( final , isPass(final) )  ) \n",
    "\n",
    "essay = 4.5\n",
    "presentation = 5.5\n",
    "final = calculateMark(essay,presentation)\n",
    "print( \"final grade: {} ({})\".format( final , isPass(final) )  ) \n",
    "\n"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Exercise 4.2.\n",
    "\n",
    "Import the math library, as follows: \n",
    "\n",
    "```\n",
    "from math import *\n",
    "```\n",
    "\n",
    "This command simply imports all the available functions from the math library. Use the functions ‘log10()’, ‘pow()’, ‘sqrt()’ and ‘cos()’ to generate the following numbers: \n",
    "\n",
    "* The base-10 logarithm of 5.\n",
    "* 3 raised to the power of 4\n",
    "* The square root of 144\n",
    "* The cosine of 60 radians."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": [
    "from math import *\n",
    "\n",
    "\n",
    "print( str( log10(20) )  )\n",
    "print( str( pow( 3 , 4 ) ) )\n",
    "print( str( sqrt( 144 ) ) )\n",
    "print( str( cos( 60 ) ) )\n",
    "\n"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Exercise 4.3.\n",
    "\n",
    "Write a function which can convert a given temperature in degrees Celcius into the equivalent in Fahrenheit. Use the following formula: F = 1.8 * C + 32.\n",
    "\n",
    "Once the function is ready, test it with a number of values. 20 degrees Celcius ought to be converted into 68 degrees Fahrenheit, and 37 degrees Celcius should equal 98.6 degrees Fahrenheit."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": [
    "def celciusToFahrentheit( celcius ):\n",
    "    fahrenheit = 1.8 * celcius + 32 \n",
    "    return round( fahrenheit , 1 )\n",
    "\n",
    "print( '{} degrees Celcius is {} degrees in Fahrenheit'.format( 20 , celciusToFahrentheit(20) ))\n",
    "print( '{} degrees Celcius is {} degrees in Fahrenheit'.format( 37 , celciusToFahrentheit(37)  )) \n",
    "    "
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Exercise 4.4.\n",
    "\n",
    "Following Pythagoras' theorem (A<sup>2</sup> + B<sup>2</sup> = C<sup>2</sup>), calculate the length of the hypothenuse in a right trangle in which the other two sides have a length of 6 and 7. Make use of the math module. "
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": [
    "from math import *\n",
    "\n",
    "A = 6\n",
    "B = 7\n",
    "\n",
    "C2 = pow( 6 , 2 ) + pow( 7 , 2 )\n",
    "C = sqrt( C2 )\n",
    "\n",
    "print(C)\n"
   ]
  }
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