## rev/ooo writeup

### Overview
The program defines many functions whose names are different Unicode "o" characters.
It asks for a flag and then checks each adjacent character pair against a list of
integers. The trick is that the index into the list always simplifies to the loop
index, so the check reduces to a simple sum of adjacent character codes.

### Key observations
- The functions are basic arithmetic:
  - `о(a,b)=a+b`, `ο(a,b)=a-b`, `օ(a,b)=a*b`, `ȯ(a,b)=a%b`, `ơ(a,b)=a^b` (xor),
    and `ὄ(a,b)=a`, `ὂ(a,b)=b`.
- In the loop:
  - `ὄ(ό,ὃ)` returns `ord(guess[i])` and `ὂ(ό,ὃ)` returns `ord(guess[i+1])`.
  - The list index is `ơ(i, ȯ(օ(ό,ὃ), ό))` which is `i XOR ((ord[i]*ord[i+1]) % ord[i])`.
  - For any positive `x`, `(x*y) % x == 0`, so the index simplifies to `i XOR 0 == i`.
  - The check becomes `ord(guess[i]) + ord(guess[i+1]) == L[i]`.

### Solving
Let `L` be the list in the script. We know the standard prefix `lactf{`, and it
already satisfies the first 6 sums. That fixes the first character, and the rest
follow deterministically:

```
chars[0] = ord('l')
chars[i+1] = L[i] - chars[i]
```

### Script
```python
L = [205, 196, 215, 218, 225, 226, 1189, 2045, 2372, 9300, 8304, 660, 8243,
     16057, 16113, 16057, 16004, 16007, 16006, 8561, 805, 346, 195, 201, 154,
     146, 223]

chars = [ord('l')]
for i in range(len(L) - 1):
    chars.append(L[i] - chars[i])

flag = ''.join(chr(c) for c in chars)
print(flag)
```

### Flag (escaped)
The resulting flag contains non-ASCII Unicode "o" letters. In escaped form:

```
lactf{g\u043e\u03bf\u0585\u1ecf\u01a1\u00f3\u1f40\u1f79\u1f78\u1f41\u1f43\u1f44\u1f42\u022f\u00f6d_j0b}
```
Final flag:
```
lactf{gоοօỏơóὀόὸὁὃὄὂȯöd_j0b}
```

To print the exact flag, run the script above (or decode the escapes).