{
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   "cell_type": "markdown",
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   "source": [
    "```\n",
    "$$\n",
    "\\begin{align}\n",
    "\\sum_{k=1}^{\\infty} \\frac{1}{k^2} = \\frac{\\pi^2}{6}\n",
    "\\end{align}\n",
    "$$\n",
    "```"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "$$\n",
    "\\begin{align}\n",
    "\\sum_{k=1}^{\\infty} \\frac{1}{k^2} = \\frac{\\pi^2}{6}\n",
    "\\end{align}\n",
    "$$"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "```\n",
    "$$\n",
    "\\newcommand{\\rot}[1]{\\nabla\\times #1}\n",
    "\\newcommand{\\pdfrac}[2]{\\frac{\\partial #1}{\\partial #2}}\n",
    "\\begin{align}\n",
    "  \\mathbf{D} &= 0 \\\\\\\n",
    "  \\mathbf{B} &= 0 \\\\\\\n",
    "  \\rot{\\mathbf{E}} &= - \\pdfrac{\\mathbf{B}}{t} \\\\\\\n",
    "  \\rot{\\mathbf{H}} &= \\pdfrac{\\mathbf{D}}{t}\n",
    "\\end{align}\n",
    "$$\n",
    "```"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "$$\n",
    "\\newcommand{\\rot}[1]{\\nabla\\times #1}\n",
    "\\newcommand{\\pdfrac}[2]{\\frac{\\partial #1}{\\partial #2}}\n",
    "\\begin{align}\n",
    "  \\mathbf{D} &= 0 \\\\\\\n",
    "  \\mathbf{B} &= 0 \\\\\\\n",
    "  \\rot{\\mathbf{E}} &= - \\pdfrac{\\mathbf{B}}{t} \\\\\\\n",
    "  \\rot{\\mathbf{H}} &= \\pdfrac{\\mathbf{D}}{t}\n",
    "\\end{align}\n",
    "$$"
   ]
  }
 ],
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