\documentclass[11pt]{article} \usepackage[T1]{fontenc} \usepackage{lmodern} \usepackage[margin=1in]{geometry} \usepackage{microtype} \usepackage{amsmath,amssymb,amsthm,mathtools} \usepackage[colorlinks=true,linkcolor=blue,citecolor=blue,urlcolor=blue]{hyperref} \hypersetup{pdftitle={The Matrix Multiplication Bound omega <= 9/4 over Associative Rings},pdfauthor={},pdfsubject={AI-generated manuscript on an integral extension of the OpenAI matrix multiplication proof}} \ifdefined\pdfinfoomitdate\pdfinfoomitdate=1\fi \ifdefined\pdftrailerid\pdftrailerid{}\fi \newtheorem{theorem}{Theorem}[section] \newtheorem{lemma}[theorem]{Lemma} \newtheorem{proposition}[theorem]{Proposition} \theoremstyle{remark} \newtheorem{remark}[theorem]{Remark} \DeclareMathOperator{\rk}{R} \newcommand{\Z}{\mathbb Z} \newcommand{\Q}{\mathbb Q} \newcommand{\C}{\mathbb C} \newcommand{\F}{\mathbb F} \newcommand{\eps}{\varepsilon} \newcommand{\res}{\preceq} \newcommand{\tp}[1]{^{\otimes #1}} \numberwithin{equation}{section} \title{The Matrix Multiplication Bound\\$\omega\leq9/4$ over Associative Rings} \author{} \date{} \begin{document} \maketitle \begin{abstract} OpenAI's auxiliary-separation argument gives the matrix multiplication exponent bound $9/4$ over the complex numbers \cite{OAI,OAILean}; our earlier extension establishes the same bound over every field \cite{Fields}. We describe an integral version of that argument. Its stronger intermediate conclusion is a bound on exact tensor rank over $\Z$, which supplies the same exponent upper bound over every associative unital ring. The zero ring is included using an explicit zero-cost program and the real-infimum convention in the formal definition. The changes are a primitive tensor semiring for spectral detection, coefficient extraction and finite free descent, and coprime patching of unnormalized Fourier and interpolation constructions. The numerical exponent and the underlying profile-growth argument are those of OpenAI. \end{abstract} \noindent\textbf{Verification status.} The full upper-bound theorem, including the zero ring, has compiled and passed its axiom audit, fresh-kernel replay, and frozen-specification Comparator with all bundled checkers. These checks validate formal declarations, not this prose document. \paragraph{AI disclosure.} This manuscript is AI-generated. The proof development and Lean formalization were produced with Codex under human direction. Attribution to the underlying OpenAI proof and the previous field extension is given below; no claim of independent numerical improvement or human peer review is made. \section{Statement and contribution} For an associative unital ring $R$, define $\omega(R)$ using division-free arithmetic programs: addition, subtraction, and multiplication each cost one operation; input and constant gates cost zero. The order of factors in a multiplication gate is significant. An exponent $\tau$ is admissible when \[ \forall\eps>0\ \exists C>0\ \forall n\geq1\ \exists P_n:\quad P_n\text{ computes matrix multiplication over }R,\qquad \operatorname{cost}(P_n)\leq Cn^{\tau+\eps}. \] Correctness means correctness for every pair of input matrices of the specified size. The exponent is the real-valued \texttt{sInf} of admissible exponents, with the convention for the zero ring explained below. This is the arithmetic model used in the OpenAI Lean development, with its scalar type generalized from a field to a ring. Write $M_n$ for the square matrix multiplication tensor and $\rk_\Z(T)$ for exact tensor rank with integer coefficient vectors. Put \[ \nu_\Z=\inf_{n\geq2}\log_n\rk_\Z(M_n). \] A tensor identity here is equality at every coefficient, not merely agreement of the corresponding functions over finite fields. \begin{theorem}\label{thm:main} The exact integer coefficient rank exponent satisfies $\nu_\Z\leq9/4$. Consequently, for every associative unital ring $R$ and every $\eps>0$, there are division-free arithmetic programs computing square matrix multiplication with cost $O_{R,\eps}(n^{9/4+\eps})$. For every such $R$, the formally defined exponent satisfies \[ \omega(R)\leq\frac94. \] \end{theorem} \begin{remark}[The zero ring and the real infimum]\label{rem:zero-ring} In the zero ring, one free constant-zero register supplies every output, giving a correct program of cost zero. Every real exponent is therefore admissible. The admissible set is $\mathbb R$, which is not bounded below; Mathlib's real-valued \texttt{sInf} convention gives $\omega(R)=0$. The extended-real infimum would instead be $-\infty$. For nontrivial rings, admissible exponents are bounded below by $2$, so the usual infimum interpretation applies. The integral argument handles that case; the zero-ring case uses the explicit program and the stated convention. \end{remark} OpenAI supplies the complex-field bound, auxiliary separation, determinant and sector constructions, and the real profile-growth argument \cite{OAI,OAILean}. The previous field extension changes the Fourier period in positive characteristic and descends from an algebraic closure through a fixed finite extension \cite{Fields}. We do not infer Theorem~\ref{thm:main} from the existence of solutions over all fields. Instead we construct and patch integer coefficient identities. This also handles rings with zero divisors, nilpotents, and noncommutative multiplication. The coefficient algebras used in the proof remain commutative. \section{The integral spectral setting} Write $U\res T$ if three integer linear maps restrict $T$ to $U$. Pass to tensors modulo mutual restriction, with direct sum as addition and tensor product as multiplication. Let $\mathcal S$ be the subsemiring consisting of zero and the classes satisfying $1\res T$. We call these classes \emph{unit-dominating}. A tensor with a coefficient $1$ or $-1$ is unit-dominating. This restriction on the spectral setting matters. The nonzero scalar tensor with coefficient $2$ does not restrict over $\Z$ to the scalar tensor $1$: such a restriction would give $2abc=1$ for integers $a,b,c$. Thus nonzero tensors cannot simply be treated as positive spectral objects in the field proof. For nonzero $T\in\mathcal S$ one has \[ 1\res T\res\langle\rk_\Z(T)\rangle, \] where $\langle m\rangle$ denotes the diagonal tensor of $m$ copies of $1$. These comparisons give precisely the cofinality and positivity used by the detecting-character argument of \cite[Appendix~A]{OAI}. The order of diagonal tensors is the ordinary order of their sizes, as follows from flattening over $\Q$. Flattening gives $\nu_\Z\geq2$; the naive multiplication scheme gives $\nu_\Z\leq3$. The detecting-character proof therefore runs on $\mathcal S$: for $d\geq2$ and an integer $0\leq k0$. We also use a literal Bezout patch. If $d_1,\ldots,d_s$ generate the unit ideal in $\Z$, their $k$th powers do too. Choose integers $u_j$ with $\sum_j u_jd_j^k=1$. Concatenating rank decompositions for $d_j^kT\tp{k}$, and multiplying one local map by $u_j$, gives a decomposition for $T\tp{k}$. This is a coefficient identity; it does not divide by any $d_j$ or treat scalar multiplication as a number of direct-sum copies. \section{Integral convolution and Fourier separation} \subsection{Interpolation with coprime norms} For positive integers $a,b$, let $C(a,b)$ be the polynomial multiplication tensor with coefficients $[i+j=\ell]$, and put $h=a+b-1$. The required statement is an asymptotic rank bound, not a rank-$h$ decomposition over $\Z$ at the first power. \begin{proposition}\label{prop:convolution} For each $a,b$ there is a positive integer $K_{a,b}$ such that \[ \rk_\Z\bigl(C(a,b)\tp{k}\bigr)\leq K_{a,b}h^k \qquad(k\geq0). \] Every normalized nonnegative character monotone under restriction obeys $\chi(C(a,b))\leq h$. \end{proposition} \begin{proof} Fix a prime $p$. Choose a finite extension of $\F_p$ with at least $h$ elements and a power basis, then lift its monic minimal polynomial to a monic $f\in\Z[t]$. The quotient $E=\Z[t]/(f)$ is finite free of some positive rank $D$, and its basis specializes to the finite-field basis. Choose lifts $v_1,\ldots,v_h$ of distinct residue elements. Write $V$ for their Vandermonde matrix and $\Delta=\det V$. Evaluation followed by $\operatorname{adj}(V)$ gives an $h$-term scheme for $\Delta C(a,b)$ over $E$. Let $M_\Delta$ be the integer matrix of multiplication by $\Delta$ in the chosen basis, and put $d=\det M_\Delta$. If $w$ is the element with coordinate vector $\operatorname{adj}(M_\Delta)[1]$, then $\Delta w=d\,1$. Multiplying the output map by $w$ therefore gives an $h$-term scheme for $dC(a,b)$ over $E$, without passing to a localization. Modulo $p$, the nodes remain distinct. Thus $\Delta$ is nonzero in the residue field, multiplication by it is invertible, and $p\nmid d$. Taking powers in this fixed $E$ and applying Lemma~\ref{lem:descent} gives \[ \rk_\Z\bigl(d^k C(a,b)\tp{k}\bigr)\leq D^2h^k. \] Perform this construction for each prime. No prime divides all resulting clearing integers, so the ideal they generate is $\Z$. Membership of $1$ in that ideal uses only a finite subfamily $d_1,\ldots,d_s$. Fix this subfamily and its algebras before varying $k$. The Bezout patch gives the assertion with $K_{a,b}=\sum_jD_j^2$. Taking $k$th roots of the character inequality removes this fixed constant. \end{proof} \subsection{Two unnormalized Fourier periods} For $M\geq1$ matched sectors, take $L=5M$ and use each period $q\in\{L,L+1\}$. Work in the finite free cyclotomic algebra $E_q=\Z[z]/(\Phi_q(z))$, with $\zeta$ the image of $z$. It is a unit and satisfies the unnormalized identity \[ \sum_{r=0}^{q-1}\zeta^{re}= \begin{cases}q,&q\mid e,\\0,&q\nmid e.\end{cases} \] Apply the substitutions of \cite[Proposition~3.1]{OAI}, omitting their factor $1/q$. The relevant phases have absolute value at most $3(M-1)0$, the retained laws include symmetry, row concavity, shifted tripling \[ P(a,3b+a-1)\geq3P(a,b), \qquad P(a,b)\leq(a+b-1)^{1/t}. \] OpenAI's real diagonal-growth argument forces $t\leq3/4$, hence $\chi(M_n)\leq n^{9/4}$. Detecting characters from Section~2 then give $\nu_\Z\leq9/4$. This step invokes their proof rather than supplying a new profile inequality or a better numerical exponent. Fix a block size $u\geq2$ and an integer rank-$r$ scheme with $r