title: Problem 282
date: 2010/03/12 17:00:00
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# [Problem 282](https://projecteuler.net/problem=282)
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[Xem đề gốc (tiếng Anh)](https://projecteuler.net/problem=282)

## **Hàm Ackermann**

Hàm Ackermann: $A(0,n) = n+1$; $A(m,0) = A(m-1,1)$; $A(m,n) = A(m-1, A(m, n-1))$.

Tính $\sum_{n=0}^{6} A(n,n) \pmod{14^8}$.

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