This website is a semi-functional mirror of the original Project Euler. More information is available on GitHub.
Integer partition equations
Problem 207
Published on 06 September 2008 at 02:00 pm [Server Time]
For some positive integers k, there exists an integer partition of the form 4t = 2t + k,
where 4t, 2t, and k are all positive integers and t is a real number.
The first two such partitions are 41 = 21 + 2 and 41.5849625... = 21.5849625... + 6.
Partitions where t is also an integer are called perfect.
For any m ≥ 1 let P(m) be the proportion of such partitions that are perfect with k ≤ m.
Thus P(6) = 1/2.
In the following table are listed some values of P(m)
P(5) = 1/1
P(10) = 1/2
P(15) = 2/3
P(20) = 1/2
P(25) = 1/2
P(30) = 2/5
...
P(180) = 1/4
P(185) = 3/13
Find the smallest m for which P(m) < 1/12345
Go to back to Problems