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Combinatoric selections
Problem 53
Published on 26 September 2003 at 06:00 pm [Server Time]
There are exactly ten ways of selecting three from five, 12345:
123, 124, 125, 134, 135, 145, 234, 235, 245, and 345
In combinatorics, we use the notation, 5C3 = 10.
In general,
nCr = |
n! r!(n−r)! |
,where r ≤ n, n! = n×(n−1)×...×3×2×1, and 0! = 1. |
It is not until n = 23, that a value exceeds one-million: 23C10 = 1144066.
How many, not necessarily distinct, values of nCr, for 1 ≤ n ≤ 100, are greater than one-million?
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