程式語言 - LeetCode - C - 1137. N-th Tribonacci Number

參考資訊：
https://www.cnblogs.com/grandyang/p/14864666.html

題目：


解答：

int tribonacci(int n)
{
    int c0 = 0;
    int c1 = 1;
    int c2 = 1;
    int cc = 0;

    if (n < 2) {
        return n;
    }
    
    for (cc = 2; cc < n; cc++) {
        int t = c0;

        c0 = c1;
        c1 = c2;
        c2 = t + c0 + c1;
    }

    return c2;
}