參考資訊:
https://www.cnblogs.com/cnoodle/p/14503186.html
題目:

解答:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* struct TreeNode *left;
* struct TreeNode *right;
* };
*/
int dfs(struct TreeNode *n, int *r, int m)
{
if (!n) {
return -1;
}
if (n->val >= m) {
(*r) += 1;
m = n->val;
}
dfs(n->left, r, m);
dfs(n->right, r, m);
return 0;
}
int goodNodes(struct TreeNode* root)
{
int r = 0;
if (!root) {
return 0;
}
dfs(root, &r, root->val);
return r;
}