for all characters
for all characters( string value, iterator value, iterator counter ) statement;
for all characters( string value, iterator value, iterator counter ) {statements; }
The loop works through all elements in the set provided in the 1st function parameter. If the set is empty, then the loop will not be executed. This loop will not step into nested parameter elements.
Indirect parameter passing is disabled
2-3
No. | Type | Description |
---|---|---|
1 input |
string | parameters Elements in this set will be provided. If a softquoted string is provided, then the contents separated by commas are individual elements. If the string is a quoted one, then it will be treated as one element. Empty sets (and string: '') make the loop skip. |
2 code |
variable :string |
iterator value This variable is updated by this function in order to provide the value of the current parameter element. It is a copied value. Modifying this variable will not influence the loop |
Opt. 3 code |
variable :string |
iterator counter This variable is updated by this function and provdes the index. It always begins with 0 and continues with 1, 2, etc. |
for all characters( Hello, greetings[] ) print( " Say: ",greetings[]);
Say: H Say: e Say: l Say: l Say: o
Manipulation while inside the loop:
1. The iterator cannot be manipulated. It will be overwritten at the next loop round.
2. If the iterator is deleted inside the loop, it will be reinstated at the next loop round. This applies to all loop variables.
3. If the target variable name is deleted, or its members are deleted / added, then the loop will end. If some of the members are removed, it will have an impact such as fewer loop cycles. Since the members are sorted in alphabetical order, the whole list of members may shift accordingly. Therefore I recommend not to manipulate this variable while inside the loop.
Inside the loop: If the affected variable is deleted or a member variables removed, then the loop will do a premature end.